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goldenfox [79]
3 years ago
15

How do you think the atomic radii will change as electrons are added to a shell?

Chemistry
2 answers:
Korvikt [17]3 years ago
6 0
As electrons are added to the valence shell, an extra proton (i.e fundamental, positively charged nuclear particle) is added to the element's nucleus. As electrons add and Z the atomic number increases 1 by 1, nuclear charge WINS, and electronic radii contract.
kirill115 [55]3 years ago
3 0

Answer:

As electrons are added to the valence shell, an extra proton (i.e fundamental, positively charged nuclear particle) is added to the element's nucleus. As electrons add and Z the atomic number increases 1 by 1, nuclear charge WINS, and electronic radii contract.

Explanation:

Hope this helps you

Crown me as brainliest:)

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Calcium and water form calcium hydroxide and hydrogen gas also called what type of reaction
Gekata [30.6K]
Reaction of calcium with water
Calcium reacts slowly with water. This is in contrast with magnesium, immediately above calcium in the periodic table, which is virtually unreactive with cold water. The reaction forms calcium hydroxide, Ca(OH)2 and hydrogen gas (H2).
4 0
3 years ago
The shape of a liquid's meniscus is determined by __________. the viscosity of the liquid the type of material the container is
Tanya [424]

In the case of the liquid meniscus, a concave meniscus that is what one usually observes takes place when the molecules of the liquid are fascinated towards the container. This takes place with water and a glass tube. A convex meniscus takes place when the molecules exhibit a stronger attraction with each other in comparison to the container, as in the case of glass and mercury.  

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8 0
3 years ago
Can someone help me please:)
docker41 [41]

Answer:

what we ain't that smart

5 0
3 years ago
How many moles of \ce{Fe2O3}FeX 2 ​ OX 3 ​ will be produced from 27.0 \text{ g}27.0 g27, point, 0, start text, space, g, end tex
ira [324]

Answer : The number of moles of Fe_2O_3  produced will be, 0.241 moles.

Solution : Given,

Mass of Fe = 27.0 g

Molar mass of Fe = 56 g/mole

First we have to calculate the moles of Fe.

\text{ Moles of }Fe=\frac{\text{ Mass of }Fe}{\text{ Molar mass of }Fe}=\frac{27.0g}{56g/mole}=0.482moles

Now we have to calculate the moles of Fe_2O_3

The balanced chemical reaction is,

4Fe+3O_2\rightarrow 2Fe_2O_3

From the reaction, we conclude that

As, 4 mole of Fe react to give 2 mole of Fe_2O_3

So, 0.482 moles of Fe react to give \frac{0.482}{4}\times 2=0.241 moles of Fe_2O_3

Thus, the number of moles of Fe_2O_3  produced will be, 0.241 moles.

6 0
3 years ago
One kilogram of water at 100 0C is cooled reversibly to 15 0C. Compute the change in entropy. Specific heat of water is 4190 J/K
mina [271]

Answer:

The change in entropy is -1083.112 joules per kilogram-Kelvin.

Explanation:

If the water is cooled reversibly with no phase changes, then there is no entropy generation during the entire process. By the Second Law of Thermodynamics, we represent the change of entropy (s_{2} - s_{1}), in joules per gram-Kelvin, by the following model:

s_{2} - s_{1} = \int\limits^{T_{2}}_{T_{1}} {\frac{dQ}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \int\limits^{T_{2}}_{T_{1}} {\frac{dT}{T} }

s_{2} - s_{1} = m\cdot c_{w} \cdot \ln \frac{T_{2}}{T_{1}} (1)

Where:

m - Mass, in kilograms.

c_{w} - Specific heat of water, in joules per kilogram-Kelvin.

T_{1}, T_{2} - Initial and final temperatures of water, in Kelvin.

If we know that m = 1\,kg, c_{w} = 4190\,\frac{J}{kg\cdot K}, T_{1} = 373.15\,K and T_{2} = 288.15\,K, then the change in entropy for the entire process is:

s_{2} - s_{1} = (1\,kg) \cdot \left(4190\,\frac{J}{kg\cdot K} \right)\cdot \ln \frac{288.15\,K}{373.15\,K}

s_{2} - s_{1} = -1083.112\,\frac{J}{kg\cdot K}

The change in entropy is -1083.112 joules per kilogram-Kelvin.

7 0
3 years ago
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