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tekilochka [14]
3 years ago
7

The sum of 4 consecutive integers is 50. What is the first of the 4 integers? 1 point

Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer:

11+12+13+14=50

Step-by-step explanation:

Just estimate. We know that 15 times 4 = 60, so it has to be less than that. We know that 10 times 4 is 40, so it has to be in that range. Just do trial and error to find the exact answer. I'm editing this now and I realized that I didn't answer the question. I don't know how to write the equation using N but the first integer is 11.      

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I need help pleace ​
Whitepunk [10]

Answer

<em>length = width + 15</em>

<em>Area = length * width; area is 54 square feet.</em>

<em>Two equations are:</em>

<em>L = W + 15</em>

<em>L * W = 54</em>

<em>To solve, we substitute first equation into second equation:</em>

<em>(W + 15) * W = 54</em>

<em>w^2 + 15w = 54</em>

<em>w^2 + 15w - 54 = 0</em>

<em>(w+18)(w-3) = 0</em>

<em>w = -18 or 3</em>

<em>The width cannot be negative, so 3 is the width and since length is 15 more than width, length is 18:</em>

<em />

<em>Length = 18 feet</em>

<em>Width = 3 feet</em>

<em />

<em />

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A gardener planted 5 rows of vegetables. Each row has 3 pepper plants and s squash plants. The garden contains a total of 20 pla
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(5x3)(5xs)=20
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Answer:

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Step-by-step explanation:

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