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tekilochka [14]
3 years ago
7

The sum of 4 consecutive integers is 50. What is the first of the 4 integers? 1 point

Mathematics
1 answer:
Tema [17]3 years ago
3 0

Answer:

11+12+13+14=50

Step-by-step explanation:

Just estimate. We know that 15 times 4 = 60, so it has to be less than that. We know that 10 times 4 is 40, so it has to be in that range. Just do trial and error to find the exact answer. I'm editing this now and I realized that I didn't answer the question. I don't know how to write the equation using N but the first integer is 11.      

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3 years ago
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7 0
4 years ago
Can you help me out with this one?
shepuryov [24]

Answer: 98

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Solve |3k-2|=2|k+12|
Stella [2.4K]

Answer:

k = 26   or   k = -\dfrac{22}{5}

Step-by-step explanation:

|3k - 2| = 2|k + 12|

\dfrac{|3k - 2|}{|k + 12|} = 2

|\dfrac{3k - 2}{k + 12}| = 2

3k - 2 = 2(k + 12)   or   3k - 2 = -2(k + 12)

3k - 2 = 2k + 24   or   3k - 2 = -2k - 24

k = 26   or   5k = -22

k = 26   or   k = -\dfrac{22}{5}

7 0
3 years ago
What is the approximate value of k?
lesya692 [45]

Hello from MrBillDoesMath!

Answer:

5.06

Discussion:

Angle J = 180 - (120 + 40) = 180 - 160 = 20 degrees,

From the law of sines

sin(120)/k = sin(20)/2  =>

sin(120) =  k *  (  sin(20)/2) )                (multiply both sides by "k")

k = sin(120)/  (   sin(20)/2)                    (divide both sides by sin(20)/2)

k =  (0.866) /  ( 0.171) =  5.06


Regards,  

MrB

 P.S.  I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!


6 0
3 years ago
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