Step-by-step explanation:
b^2-4b+3=0
b²-3x-b+3=0
b(b-3)-1(b-3)=0
(b-3)(b-1)=0
either
b=3 or b=1
.
2n^2 + 7 = -4n + 5
2n²+4n+7-5=0
2n²+4n+2=0
2(n²+2n+1)=0
(n+1)²=0/2
:.n=-1
.
x - 3x^2 = 5+ 2x - x^2
0=5+ 2x - x^2-x +3x^2
0=5+x+2x²
2x²+x+5=0
comparing above equation with ax²+bx +c we get
a=2
b=1
c=5
x={-b±√(b²-4ac)}/2a ={-1±√(1²-4×2×5)}/2×1
={-1±√-39}/2
To work out the profit, firstly, you have to work out the cost of buying them, which is $15 multiplied by 100, which is $1500. You then have to work out what he sold them all at, which is $29.99 multiplied by 100, which is $2999. You then have to subtract $1500 from $2999, giving you $1499. Therefore, Ace made $1499 in profit.
Hope this helps :)
Okay.. well did you try to do it on your own at least ? I help you, but what do you know already so we can go on from there.
The correct answer is 34.4
Answer:
an infinite number of solutions
Step-by-step explanation:
−3x −17 = −17 −3x
left side = right side TRUE because -3x-17 is the same as -17-3x
we can rearrange the the equation
−3x −17 +17 = −17 +17−3x, add 17 on both sides of the equations
-3x = -3x, divide both sides by (-3)
x = x
Since this equation is <u>always true ( for any number ) </u>we have <u>an infinite number of solutions</u> (since there are is an infinity of numbers.)
