Answer:
Step-by-step explanation:
Prove: That the sum of the squares of 4 consecutive integers is an even integer.
An integer is a any directed number that has no decimal part or indivisible fractional part. Examples are: 4, 100, 0, -20,-100 etc.
Selecting 4 consecutive positive integers: 5, 6, 7, 8. Then;
= 25
= 36
= 49
= 64
The sum of the squares = 25 + 36 + 49 + 64
= 174
Also,
Selecting 4 consecutive negative integers: -10, -11, -12, -13. Then;
= 100
= 121
= 144
= 169
The sum of the squares = 100 + 121 + 144 + 169
= 534
Therefore, the sum of the squares of 4 consecutive integers is an even integer.
Answer:
-11/20
Step-by-step explanation:
2 8 1
(0-— ÷ (0-—))+—
3 9 5
8
Simplify —
8/9
2 8 1
(0 - — ÷ (0 - —)) + —
3 9 5
Simplify —
2/3
2 -8 1
(0 - — ÷ ——) + —
3 9 5
2 -8
Divide — by ——
3 9
To divide fractions, write the divison as multiplication by the reciprocal of the divisor :
2 -8 2 9
— ÷ —— = — • ——
3 9 3 -8
(0--3/4)+1/5
Least Common Multiple:
20
Left_M = L.C.M / L_Deno = 5
Right_M = L.C.M / R_Deno = 4
3 • 5 + 4 -11
————————— = ———
20 20
-11/20