The polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)
<h3>Polar form of a rectangular coordinate</h3>
The polar form of a rectangular coordinate (x, y) is expressed as (rcos theta, r sin theta)
Given the coordinate (-2√3 , 2)
r = √(-2√3)²+2²
r = √12+4
r = 4
theta = tan^-1(-2/2√3)
theta = tan^-1(-1/√3)
theta = -30 degrees = 210 degrees
The polar coordinates of the point whose cartesian coordinates is (-2√3 , 2) is (4cos210, 4sin210)
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IF you are dilating about the origin, which you didn't exactly state, the new coordinates are A' (1/5, 1), B' (2/5, 1/5), C' (0, 4/5). Dilation is all about distance, so you have to move the new coordinates to whatever the scale factor is times the x and y distance. For example, A is at (1, 5), so 1/5 of 1 is 1/5, and 1/5 of 5 is 1, hence your new coordinate for A. It is a fifth of the distance from the origin as its preimage is.
Answer:
105
im sorry if its in correct I hope it is
The value of n that will make the expression equal is 13
<h3>Equations and expression</h3>
Equations are expressions separated by equal sign
Given the equation
11n = 143
Divide both sides by 11 to have;
11n/11 = 143/11
n = 13
Hence the value of n that will make the expression equal is 13
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A triangle is the best because it is sturdy. There is no "wiggle room" for the triangle to transform into another shape.
