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3 years ago

How many antinodes are in the standing wave pattern shown? 1. 2 2. 4 3. 3 4. 7 5. 5 6. 6?

Mathematics

1 answer:

Sphinxa [80]3 years ago

4 0

There's 6 antinodes here.

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If <img src="https://tex.z-dn.net/?f=%5Crm%20%5C%3A%20x%20%3D%20log_%7Ba%7D%28bc%29" id="TexFormula1" title="\rm \: x = log_{a}(

timama [110]

Use the change-of-basis identity,

$\log_x(y) = \dfrac{\ln(y)}{\ln(x)}$

to write

$xyz = \log_a(bc) \log_b(ac) \log_c(ab) = \dfrac{\ln(bc) \ln(ac) \ln(ab)}{\ln(a) \ln(b) \ln(c)}$

Use the product-to-sum identity,

$\log_x(yz) = \log_x(y) + \log_x(z)$

to write

$xyz = \dfrac{(\ln(b) + \ln(c)) (\ln(a) + \ln(c)) (\ln(a) + \ln(b))}{\ln(a) \ln(b) \ln(c)}$

Redistribute the factors on the left side as

$xyz = \dfrac{\ln(b) + \ln(c)}{\ln(b)} \times \dfrac{\ln(a) + \ln(c)}{\ln(c)} \times \dfrac{\ln(a) + \ln(b)}{\ln(a)}$

and simplify to

$xyz = \left(1 + \dfrac{\ln(c)}{\ln(b)}\right) \left(1 + \dfrac{\ln(a)}{\ln(c)}\right) \left(1 + \dfrac{\ln(b)}{\ln(a)}\right)$

Now expand the right side:

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} \\\\ ~~~~~~~~~~~~+ \dfrac{\ln(c)\ln(a)}{\ln(b)\ln(c)} + \dfrac{\ln(c)\ln(b)}{\ln(b)\ln(a)} + \dfrac{\ln(a)\ln(b)}{\ln(c)\ln(a)} \\\\ ~~~~~~~~~~~~ + \dfrac{\ln(c)\ln(a)\ln(b)}{\ln(b)\ln(c)\ln(a)}$

Simplify and rewrite using the logarithm properties mentioned earlier.

$xyz = 1 + \dfrac{\ln(c)}{\ln(b)} + \dfrac{\ln(a)}{\ln(c)} + \dfrac{\ln(b)}{\ln(a)} + \dfrac{\ln(a)}{\ln(b)} + \dfrac{\ln(c)}{\ln(a)} + \dfrac{\ln(b)}{\ln(c)} + 1$

$xyz = 2 + \dfrac{\ln(c)+\ln(a)}{\ln(b)} + \dfrac{\ln(a)+\ln(b)}{\ln(c)} + \dfrac{\ln(b)+\ln(c)}{\ln(a)}$

$xyz = 2 + \dfrac{\ln(ac)}{\ln(b)} + \dfrac{\ln(ab)}{\ln(c)} + \dfrac{\ln(bc)}{\ln(a)}$

$xyz = 2 + \log_b(ac) + \log_c(ab) + \log_a(bc)$

$\implies \boxed{xyz = x + y + z + 2}$

(C)

6 0

2 years ago

Giving 20 points and brainiest!

sladkih [1.3K]

Answer:

1/2,3/6,5/10,8/16

Step-by-step explanation:

they all equal 1/2

Im not sure if thats what it was asking but yea

6 0

3 years ago

Read 2 more answers

Solve a triangle when A=15° B=113° and b=7?

JulsSmile [24]

Let us draw a triangle ABC with A=15° ,B=113° and b=7.

Please see the attached image.

We know that the sum of interior angles of a triangle is 180 degrees. Thus, we have

$A+B+C=180\\
\\
15+113+C= 180\\
\\
C=62^{\circ}$

Apply Sine rule in the triangle ABC, we get

$\frac{a}{\sin 15}= \frac{7}{\sin 113}\\
\\
a=\frac{7 \sin 15}{\sin 113}\\
\\
a=1.97\\
\\
\text{Again apply sine rule, we get}\\
\\
\frac{c}{\sin 62}= \frac{7}{\sin 113}\\
\\
c=\frac{7 \sin 62}{\sin 113}\\
\\
c=6.71$

Therefore, we have

$a=1.97\\
c=6.71\\
C=62^{\circ}$

4 0

4 years ago

Solve for x <br> 3(x - 2) = 6x - 12

svetoff [14.1K]

Answer:x=2

Step-by-step explanation:

3(x-2)=6x-12

3x-6=6x-12

Collect like terms

6x-3x=12-6

3x=6

Divide both sides by 3

3x/3=6/3

x=2

6 0

3 years ago

Find m∠ABC = 7x - 4 and m∠BDC = 9x - 1 and and m∠ABC = 107°, find x, m∠ABC and m∠BDC.

Artyom0805 [142]

Answer:

m<BDC = 62 degrees

Step-by-step explanation:

Using the expression;

<ABC = <ABD + <DBC

107 = 7x-4 + 9x - 1

107 = 16x-5

16x = 107 + 5

16x = 112

x = 112/16

x = 7

Get m<DBC

m<BDC = 9x - 1

m<BDC = 9(7)-1

m<BDC = 63 - 1

m<BDC = 62 degrees

6 0

3 years ago