This is the concept of algebra, let the width be x
height=x-4
length=2x+10
the volume of the box is:
volume=length*width*height
=x(x-4)(2x+10)
expanding the above we get:
(x^2-4x)(2x+10)
=x^2(2x+10)-4x(2x+10)
=2x^3+2x^2-40x=264
solving the above we get real solution will be
x=6
thus we conclude that the width is x=6 inches
length=2*6+10=22 inches
height=x-4=6-4=2 inches
thus the dimension will be:
width=6 inches, length=22 inches, height=2 inches
Hello : here is a solution
It is the first choice. All you have to do is isolate A from 2A so you would divide by 2 and get A=bh/2
Multiply length times width to find the area. 6.5x11= 71.5
Answer:
Correct integral, third graph
Step-by-step explanation:
Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.
Given : ∫ tan²(θ)sec²(θ)dθ
Applying u-substitution : u = tan(θ),
=> ∫ u²du
Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1
Substitute back u = tan(θ) : tan^2+1(θ)/2+1
Simplify : 1/3tan³(θ)
Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.