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galina1969 [7]
3 years ago
14

1. Which equation represents the relationship shown in the table below? (1 point)

Mathematics
1 answer:
Alex17521 [72]3 years ago
5 0
The third one is correct
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The height of a box that bill is shipping is 4 inches less than the width of the box. the length is 10 inches more than twice th
8090 [49]
This is the concept of algebra, let the width be x
height=x-4
length=2x+10
the volume of the box is:
volume=length*width*height
=x(x-4)(2x+10)
expanding the above we get:
(x^2-4x)(2x+10)
=x^2(2x+10)-4x(2x+10)
=2x^3+2x^2-40x=264
solving the above we get real solution will be
x=6
thus we conclude that the width is x=6 inches
length=2*6+10=22 inches
height=x-4=6-4=2 inches
thus the dimension will be:
width=6 inches, length=22 inches, height=2 inches


6 0
3 years ago
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For what values of a and b is the line 3x y=b tangent to the curve y=ax3 when x=3?
Sav [38]
Hello : here is a solution 

6 0
3 years ago
Need help. Thank you :”)
Agata [3.3K]

It is the first choice. All you have to do is isolate A from 2A so you would divide by 2 and get A=bh/2

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6.5yd and 11yd<br> please find the area
Afina-wow [57]
Multiply length times width to find the area. 6.5x11= 71.5
3 0
3 years ago
How do you do this question?
Lisa [10]

Answer:

Correct integral, third graph

Step-by-step explanation:

Assuming that your answer was 'tan³(θ)/3 + C,' you have the right integral. We would have to solve for the integral using u-substitution. Let's start.

Given : ∫ tan²(θ)sec²(θ)dθ

Applying u-substitution : u = tan(θ),

=> ∫ u²du

Apply the power rule ' ∫ xᵃdx = x^(a+1)/a+1 ' : u^(2+1)/ 2+1

Substitute back u = tan(θ) : tan^2+1(θ)/2+1

Simplify : 1/3tan³(θ)

Hence the integral ' ∫ tan²(θ)sec²(θ)dθ ' = ' 1/3tan³(θ). ' Your solution was rewritten in a different format, but it was the same answer. Now let's move on to the graphing portion. The attachment represents F(θ). f(θ) is an upward facing parabola, so your graph will be the third one.

7 0
3 years ago
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