since BAD = 125
180-125 = 55 so ADC = 55
ADC = GHE so GHE = 55 degrees
Answer:
188π in^2
Step-by-step explanation:
Surface area of the rocket = surface area of the cone + surface area of the cylinder
Surface area of a cone = πr(r+h^2+r^2)
r = 8/2 = 4 in
4π( 4 + 3^2 + 4^2) =
4π ( 4 + 9 + 16) = 116π in^2
Surface area of a cylinder = 2πrh+2πr^2
(2 x n x 4 x 5) + (2 x n x 16)= 72π in^2
116 + 72 = 188π in^2
I think it is 25650
I read the quistion carefully
Answer:
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