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maxonik [38]
4 years ago
7

PLEASE HELLPPPPPPPP.......

Mathematics
2 answers:
Ksivusya [100]4 years ago
5 0

Answer:

The other person had the best answer for your question but I think it might be c=9

Vanyuwa [196]4 years ago
4 0

Answer:

11in

Step-by-step explanation:

a^2+b^2=c^2  when c is the hypotenuse

10^2+sqrt21^2=c^2

100+21=c^2

121=c^2

11=c

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I’ll put you as brainliest
kari74 [83]

The law of an object moving with constant acceleration is

s(t)=s_0+v_0t+\dfrac{1}{2}at^2

Where s is space, t is time, s_0 is the initial position, v_0 is the initial velocity and a is the acceleration.

In this case, if we choose a reference grid with the vertical axis pointing upwards, the acceleration of gravity will point downwards (and thus be negative). The initial position is zero, because the rocket is on the ground, and the initial velocity is 100 (positive because pointing upwards).

So, its law is

h(t)=100t-\dfrac{1}{2}gt^2

(I changed s for h since the rocket is moving vertically, so its position is actually its height. Also, g is the acceleration due to gravity).

The rocket hits the ground if its height is zero, so if we set h=0 we have

0=100t-\dfrac{1}{2}gt^2 \iff t(100-\dfrac{1}{2}gt)=0

Solving for t, we have either t=0, or

100-\dfrac{1}{2}gt=0 \iff 100=\dfrac{1}{2}gt \iff 200=gt \iff t=\dfrac{200}{g}

The solution t=0 means that at the beginning the rocket is on the ground. So, we're interested in the other solution. Considering that g is about 32.2 feet/s^2, we have

t=\dfrac{200}{g}\approx \dfrac{200}{32.2}\approx 6.21

3 0
3 years ago
PLEASE! I WILL GIVE BRAINLIEST THIS IS DUE TONIGHT! Alicia analyzes the quadrilaterals shown on the coordinate plane. Which equa
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I think it’s A because it’s not supplementary I’m not sure
4 0
4 years ago
Simplify 4a+3b-(-2a-3b)
Talja [164]
4a+3b-(-2a-3b)
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What’s the question?
3 0
3 years ago
Find the m∠BCA, if m∠DCE = 70° and m∠EDC = 50°.<br><br> 50°<br> 60°<br> 70°<br> 80°
lara [203]
Because of the parallel lines, angles A and DCE are congruent.
Also, angles E and BCA are congruent.
That makes angles B and D congruent.

m<DCE = 70 and m<EDC = 50, so m<E = 60

m<BCA = m<E = 60
5 0
3 years ago
Read 2 more answers
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