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Anit [1.1K]
3 years ago
12

Help pls I'm really busy and if I get ur help you will make my whole day :(

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
6 0

1. 84

2. 300

3. 6

4. 4

5. 48

6. 80,000

Step-by-step explanation: I hope this made your day ツ

aniked [119]3 years ago
5 0

Answer:

1.) 7 ft = 84 in   2.) 100 yd= 300 ft  3.) 96 oz= 6 lbs  4.) 32 fl oz= 4 c  5.) 48 oz            6.) 80,000 lbs

Step-by-step explanation:

You have to use conversation rates.

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How do I solve -3(3+x)+(x-6)=-4 ?
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\huge\boxed{x=-\frac{11}{2}}

Start by distributing the -3 to the (3+x). -3(3) + (-3)(x) + (x-6) = -4

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7 0
3 years ago
(12a^(2) - 3)/(2)*(2a + 1)^(-2)*((6)/((2a + 1)))^(-1)
Elena L [17]

Answer:

\frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

Step-by-step explanation:

\frac{(12a^2-3)}{2*(2a+1)^{-2}}*\frac{6}{(2a+1)^{-1} }\\ = \frac{(12a^2-3)}{2 * \frac{1}{(2a+1)^{2} }} * \frac{6}{\frac{1}{2a+1}  }\\ =\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}\\=\frac{(12a^2-3)(2a+1)^{2}}{2} * \frac{6}{2a+1}

= \frac{(12a^2-3)(4a^{2} + 1 + 2 (2a)(1))}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{2} * \frac{6}{2a+1}\\= \frac{(12a^2-3)(4a^{2} + 1 + 4a)}{1} * \frac{3}{2a+1}\\= \frac{3(12a^2-3)(4a^{2} + 1 + 4a)} {2a+1}\\\\= \frac{3(12a^2(4a^{2} + 1 + 4a) - 3 (4a^{2}+1+4a)} {2a+1}\\= \frac{3(48a^{4}+12a^{2}+48a^{3}  - 12a^{2} -12 - 4a)} {2a+1}\\= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a)} {2a+1}

= \frac{144a^{4}+36a^{2}+144a^{3}  - 36a^{2} - 36 - 12a} {2a+1}\\= \frac{144a^{4}+144a^{3} - 36 - 12a} {2a+1}\\

6 0
3 years ago
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