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3 years ago

Simplify 4a+3b-(-2a-3b)

Mathematics

1 answer:

Talja [164]3 years ago

8 0

4a+3b-(-2a-3b)
=4a+3b+2a+3b
=6a+6b
=6(a+b)

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The official all-time high temperature in Osoyoos, B.C., was 43°C in July 1998. The official all-time low temperature was –21°C

lesantik [10]

Answer: 64°C

Step-by-step explanation:

Official all-time high temperature = 43°C

Official all-time low temperature = –21°C

The difference between the two temperatures will be calculated by subtracting the low temperature from the high temperature. This will be:

= 43°C - (-21°C)

= 43°C + 21°C

= 64°C

6 0

3 years ago

What's the solution for y+1/2=3/4

creativ13 [48]

$\frac{y+1}{2} = \frac{3}{4}$

2(y+1) = 3 LCD is 4

2*y + 2*1 = 3

2y + 2 = 3

2y = 3 - 2

2y = 1

y = 1 / 2

6 0

3 years ago

Help,<br> what do i put in the blanks

Vikki [24]

For saturday’s empty box it’s 35
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4 0

2 years ago

Read 2 more answers

Factor the expression.

tiny-mole [99]

B. (k+10f)(k-5f) you can tell in 2 ways. 1. if the second sign is neg then the signs in the factors are going to be one neg and one positive so that knocks out C and D. Then you look at the second term and since the 5 is positive then the 10 has to be positive so you end up with a positive 5kf.

The second way is to FOIL them out. When you check B you get $k^{2} -5kf+10kf- 50f^{2}$ combine your like terms and you have your original expression of $k^{2} +5kf-50 f^{2}$

Hope that helps

3 0

3 years ago

A rectangular sign has length of 3 and 1/2 ft and a width of 1 and 1/8 ft. Will the area of the sign be greater or less than 3 a

zavuch27 [327]

Answer:

$Area = 3\dfrac{15}{16}\ sq\ ft$

Area is greater than $3\frac{1}{2}$ sq ft.

Step-by-step explanation:

Length of rectangular sign board = $3\frac{1}{2}$ ft

Width of rectangular sign board = $1\frac{1}{8}$ ft

Area of a rectangle is given by the formula:

$A = Length \times Width$

To find the area, we are going to multiply $3\frac{1}{2}$ with $1\frac{1}{8}$ .

$1\frac{1}{8}$ is greater than 1.

Therefore the multiplication will be greater than $3\frac{1}{2}$ .

Hence, we can say that area will be greater than $3\frac{1}{2}$ sq ft.

Area of the sign:

$A = 3\dfrac{1}{2}\times 1\dfrac{1}8\\\Rightarrow A = \dfrac{7}{2}\times \frac{9}8\\\Rightarrow A = \dfrac{63}{16}\\\Rightarrow A = 3\dfrac{15}{16}\ sq\ ft$

8 0

2 years ago