Question

√27 + √48 - √12 the correct answers for this please​

Answer 1

Answer:

$\sqrt{27} + \sqrt{48} - \sqrt{12} \\ \sqrt{3 \times 3 \times 3} + \sqrt{2 \times 2 \times 2 \times 2 \times 3} - \sqrt{2 \times 2 \times 3} \\ 3 \sqrt{3} + 4 \sqrt{3} - 2 \sqrt{3} \\ 7 \sqrt{3} - 2 \sqrt{3} \\ \boxed{5 \sqrt{3}}$

5√3 is the right answer.

Answer 2

Answer:

5$\sqrt{3}$

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals

$\sqrt{27}$ = $\sqrt{9(3)}$ = $\sqrt{9}$ × $\sqrt{3}$ = 3$\sqrt{3}$

$\sqrt{48}$ = $\sqrt{16(3)}$ = $\sqrt{16}$ × $\sqrt{3}$ = 4$\sqrt{3}$

$\sqrt{12}$ = $\sqrt{4(3)}$ = $\sqrt{4(3)}$ = $\sqrt{4}$ × $\sqrt{3}$ = 2$\sqrt{3}$

Then

$\sqrt{27}$ + $\sqrt{48}$ - $\sqrt{12}$

= 3$\sqrt{3}$ + 4$\sqrt{3}$ - 2$\sqrt{3}$

= 5$\sqrt{3}$