Jane multiplies her number by three and subtracts 2.

Mathematics

1 answer:

katrin [286]3 years ago

3 0

Answer:

Let the number they chose be 'x'.

Result of Jane = $3x -2$

Result of Elliot = $2x+3$

Given that,

The product of their result = 110

$or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}$

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BlackZzzverrR [31]

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3 years ago

Help asap do all show work

love history [14]

y=-x

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15.

i don’t wanna do all sorry it’s a lot of work so i’ll tell u how to do it instead. first write it in slope intercept form which is

y-y1=m(x-x1)