All categories

3 years ago

Jane multiplies her number by three and subtracts 2.

Mathematics

1 answer:

katrin [286]3 years ago

3 0

Answer:

Let the number they chose be 'x'.

Result of Jane = $3x -2$

Result of Elliot = $2x+3$

Given that,

The product of their result = 110

$or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}$

You might be interested in

Help me so confused?

Eva8 [605]

BD is 31 degrees because it is the same.

ADB is 90-31 because it is a right angle ( 59 degrees)

DEC is 180 - (31*2) because the 180 is of the trangle and the 31 is the same on the other side so times 2 then removed from 180

7 0

3 years ago

Tony has 23 gallon of milk. He wants to equally share the milk between 3 milkshakes. Which expression represents the amount of m

DiKsa [7]

Answer:

Amount of milk in each milkshake = 7 2/3 gallons

Step-by-step explanation:

Gallons of milk = 23 (given)

Number of Milkshakes = 3

Because the gallons of milk were shared equally,

Amount of milk in each milkshake = 23/3 = 7 2/3 gallons of milk

5 0

3 years ago

ILL GIVE BRAINLEST- select each classification that describes the triangle shown.

denis23 [38]

Answer:

Obtuse, isosceles

Step-by-step explanation:

Classify. Two same length sides make it isosceles

A larger angle than 90° make it obtuse

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

7 0

2 years ago

There are 1,760 yards in a mile. How many full laps would Danny have to run around the block to run a mile?

oee [108]

Answer:

how many yards is the track

4 0

3 years ago

Q1.Simplify:

solniwko [45]

$\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\$

$\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\$

$\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2} \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625$

6 0

2 years ago

Read 2 more answers