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boyakko [2]
3 years ago
15

Jane multiplies her number by three and subtracts 2.

Mathematics
1 answer:
katrin [286]3 years ago
3 0

Answer:

Let the number they chose be 'x'.

Result of Jane = 3x -2

Result of Elliot = 2x+3

Given that,

The product of their result = 110

or, (3x-2)(2x+3) = 110\\or, 6x^{2} +9x-4x-6 = 110\\or, 6x^{2} +5x - 6 = 110\\or, 6x^{2} +5x - 6-110 = 0\\\\or, 6x^{2} +5x - 116 = 0\\or, 6x^{2} +29x - 24x - 116 = 0\\or, x (6x +29) -4(6x+29) = 0\\or, (x-4)(6x+29) = 0\\i.e. x=4 or x=\frac{-29}{6} \\So,~ the ~number ~they~ chose~was ~either ~4 ~or ~\frac{-29}{6}

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Maurinko [17]

Answer:

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Step-by-step explanation:

The given functions are reciprocals of the primary trig functions:

  cot(x) = 1/tan(x)

  csc(x) = 1/sin(x)

The tangent function has a period of π, and is equal to the cotangent of the complementary angle.

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<h3>a)</h3>

The given angle is an alias of -π/4, so we can write ...

  cot(7π/4) = cot(-π/4) = -cot(π/4) = -tan(π/2 -π/4) = -tan(π/4)

  -tan(π/4) = -1

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<h3>b)</h3>

  csc(-π/3) = 1/sin(-π/3) = -1/sin(π/3) = -1/(√3/2) = -2/√3

  -1/sin(π/3) = -2√3/3

6 0
2 years ago
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Lubov Fominskaja [6]

Answer:

I would say you are correct

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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katrin2010 [14]

To solve for n:

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Hope this helps! :)

8 0
4 years ago
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