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Temka [501]
3 years ago
15

a cylindrical glass holds 130 cubic centimeters of water and has a height of 6cm, what is the diameter of the class?

Mathematics
1 answer:
nadezda [96]3 years ago
3 0

Answer:

5.26

Step-by-step explanation:

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Kate bought 4 cans of soup for $2.67. How much would it cost for her to buy 10 cans?
gavmur [86]

Answer:

It would be 6.60

Step-by-step explanation:

first you have to find the price of one can, so you divided 2.67 by 4.

the answer would actually be 0.6675, but you have to stop at the tenths place for money, so in this case, it would be 0.66.

we multiply 0.66 by 10 and get 6.6 which is also 6.60

It would cost $6.60 to but 10 cans.

Idk if this helps, but I hope it does.

4 0
3 years ago
A triangle always forms __?__ angles whose sum always equals __?__.
saw5 [17]
Two 180 degrees choice A
3 0
3 years ago
Read 2 more answers
What does p equal in the following sentence: The product of 1/4 and P is negative 2?
Varvara68 [4.7K]
The answer is -8
-8*1/4=-2
8 0
3 years ago
Which letters from the table represents like terms
r-ruslan [8.4K]
B and C.

When multiplying binomials, you use a form of the distributive property. With how your lesson has it here, it formed a multiplication table instead.

If you were to complete the table with the actual values, you'd find that:
A=-8x^2
B= 12x
C= -2x
D= 3

As you can see, B and C are the only like terms, or in other words, they can be added together since they have similar variables
4 0
4 years ago
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What is the average rate of change of f over the interval -1 on a separate sheet of paper and upload the work as a photo. Show a
Anarel [89]

Answer:

Average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

Step-by-step explanation:

We need to find average rate of change of f over the interval -1 < x < 1

The function given is: f(x)= x^2-x-1

The formula used to find average rate of change is:

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}

We have, a = -1 and b = 1

Finding f(b) when b=1

f(x)=x^2-x-1\\f(1)=(1)^2-(1)-1\\f(1)=1-1-1\\f(1)=-1

Now, finding f(a), when a= -1

f(x)=x^2-x-1\\f(-1)=(-1)^2-(-1)-1\\f(1)=1+1-1\\f(-1)=2-1\\f(-1)=1

Now, putting values and finding average rate of change

Average\:rate\:of\:change=\frac{f(b)-f(a)}{b-a}\\Average\:rate\:of\:change=\frac{f(1)-f(-1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-(1)}{1-(-1)}\\Average\:rate\:of\:change=\frac{-1-1}{1+1}\\Average\:rate\:of\:change=\frac{-2}{2}\\Average\:rate\:of\:change=-1

So, average rate of change for the function f(x)= x^2-x-1 over the interval -1<x<1 is -1

4 0
3 years ago
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