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DanielleElmas [232]
2 years ago
12

9) A rectangular prism has a width of 8 cm, a height of 2 cm and a depth of 8 cm. What is the volume of the prism?

Mathematics
2 answers:
Ira Lisetskai [31]2 years ago
6 0

Answer:

It should be 128 cm

Step-by-step explanation:

netineya [11]2 years ago
6 0
The volume of rectangular prism rule is length multiplied by width multiplied by height so the answer will be
8 multiply 8 multiply 2 which is equal 128

128 is the final answer i hope it helps
Goodluck
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Math need help please
AnnyKZ [126]

Answer:

none

Step-by-step explanation:

4x - 6 = 2(2x + 3)

4x - 6 = 4x + 6

Everything cancels out meaning there are no real solutions

5 0
2 years ago
Can someone help me with this question? Thank you!
Harrizon [31]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's evaluate ~

The given expression is :

\qquad \sf  \dashrightarrow \:4x + 8

plug the value of x as 3

\qquad \sf  \dashrightarrow \:4(3) + 8

\qquad \sf  \dashrightarrow \:12 + 8

\qquad \sf  \dashrightarrow \:20

Therefore, the required value is 20

8 0
2 years ago
How much its 5+3+3×15=
AveGali [126]
=5 + 3 + 3 * 15
do multiplication first
=5 + 3 + 45
=8 + 45
=53

ANSWER: 53

Hope this helps! :)
7 0
3 years ago
Read 2 more answers
8. The area of the bigger square at the picture is 32. What is the area of
Karolina [17]

Answer:

16 is the awnser or at least I belive

8 0
3 years ago
What is the confidence interval estimate of the population mean percentage change in the price per share of stock during the fir
I am Lyosha [343]

Answer:

(-0.1059 ; - 0.0337)

Step-by-step explanation:

The data table is attached in the picture below:

These is a matched pair design ; which requires taking the difference of the two values for each sample :

The mean and standard deviation of the difference will be used to construct the confidence interval :

The mean of difference, dbar = Σx/n = - 0.0698

The standard deviation of difference, Sd ;

Sd = [√Σ(d - dbar)²/(n-1)] = 0.1054

n = sample size = 25

The confidence interval :

dbar ± [TCritical * Sd/√n]

Tcritical at 90% ; df = n -1 = 25 -1

Tcritical(90% , 24) = 1.1711

C.I = - 0.0698 ± (1.711 * 0.1054/√25)

C.I = - 0.0698 ± 0.0361

C.I = (-0.1059 ; - 0.0337)

5 0
2 years ago
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