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In-s [12.5K]
3 years ago
8

Which expression is equivalent to 91+39 ?

Mathematics
1 answer:
KIM [24]3 years ago
5 0

Answer:

130

Step-by-step explanation:

i think

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The length of a rectangular park is 20 feet longer than the width of the park. If the lenght of the park is 36 feet, what is the
lara [203]

Below is a labeled rectangle:

length = w + 20

we know length is 36 so we plug that in:

36 = w + 20

We need to isolate w and to do that we must subtract 20 from both sides:

(36 - 20) = w + (20 - 20)

16 = w + 0

w = 16

width is 16 feet

Hope this helped!

3 0
3 years ago
Use substitution to determine if the solution is correct (PINK HIGHLIGHTED ONE!!!)
mart [117]

Answer:

It is not correct.

Step-by-step explanation:

If you plug 4 in for x, you get -2*4+5=13. This simplifies to: -8+5=13. This is an untrue statement since -8+5 is actually -3, not 13.

Hope this is helpful! :)

4 0
3 years ago
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Item 19 The scale on a map is 1 cm:30 mi. The distance on the map between San Francisco, CA, and Chicago, IL, is 61.9 cm. What i
Harlamova29_29 [7]

Answer:

1857 miles.

Step-by-step explanation:

We have been given that the scale on a map is 1 cm:30 mi. The distance on the map between San Francisco, CA, and Chicago, IL, is 61.9 cm. We are asked to find the actual distance between San Francisco and Chicago.

We will use proportions to solve our given problem.

\frac{\text{Actual distance}}{\text{Map distance}}=\frac{30\text{ miles}}{1\text{ cm}}

Upon substituting map distance between San Francisco and Chicago, we will get:

\frac{\text{Actual distance}}{61.9\text{ cm}}=\frac{30\text{ miles}}{1\text{ cm}}

\frac{\text{Actual distance}}{61.9\text{ cm}}\cdot 61.9\text{ cm}=\frac{30\text{ miles}}{1\text{ cm}}\cdot 61.9\text{ cm}

\text{Actual distance}=30\text{ miles}\cdot 61.9

\text{Actual distance}=1857\text{ miles}

Therefore, the actual distance between San Francisco and Chicago is 1857 miles.

4 0
3 years ago
Can you answer ASAP PLZ answer with work
luda_lava [24]

Answer:

$43.70

Step-by-step explanation:

90.50 - 4 = 87.50

87.50 ÷ 2 = $43.70

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4 0
3 years ago
the city park department is planning to enclose a play aea. one side of the area will be against an existing building, so no fen
SVEN [57.7K]

Answer:

length = 200 m

width = 400 m

Step-by-step explanation:

Let the length of the plaing area is L and the width of the playing area is W.

Length of fencing around three sides = 2 L + W = 800

W = 800 - 2L ..... (1)

Let A is the area of playing area

A = L x W

A = L (800 - 2L)

A = 800 L - 2L²

Differentiate with respect to L.

dA/dL = 800 - 4 L

It is equal to zero for maxima and minima

800 - 4 L = 0

L = 200 m

W = 800 - 2 x 200 = 400 m

So, the area is maximum if the length is 200 m and the width is 400 m.

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3 years ago
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