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JulsSmile [24]
3 years ago
6

Which ordered pair named the location of Melinda's house?

Mathematics
1 answer:
kati45 [8]3 years ago
4 0

Answer:

B

Step-by-step explanation:

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what is three and sixty-tow thousandths rounded to the nearest hundredth and to the nearest whole number
vitfil [10]
Round 2 from the 6 and then your answer will  be 360,000.
7 0
3 years ago
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George usually takes 1.5 hours to mow his neighbor’s grass and trim the bushes. Today he has only 0.75 of the usual amount of ti
g100num [7]
Anyhoot, you can multiply 1.5 by 0.75 to find the time. And you can multiply by 60 to get 67.5 minutes, aka, 1.125 hours
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3 years ago
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Homogenized milk has a density of 1.032 kg/L and heavy cream has a density of 1.005 kg/L at 10°C. At 10°C, a container holding 8
Bumek [7]

Answer:

It's heavy cream

Step-by-step explanation:

Homogenized milk has a density of 1.032 kg/L and

heavy cream has a density of 1.005 kg/L at 10°C.

At 10°C, a container holding 8 liters of liquid weighs 8.04 kilograms

To determine which container hold homogenized milk or heavy cream and How I know?

We findo the density of the measurements given and whatever it correspond to is what it is

First mass is 8.04kg

Liquid contained is 8 litres

SInce the density is kg/L

No need for conversion

Density = mass/volume = 8.04/8= 1.005kg/L

Heavy cream has a density of 1.005 kg/L at 10°C.

Therefore it correspond

5 0
3 years ago
Both the La Plata river dolphin (Pontoporia blainvillei) and
Citrus2011 [14]

Answer:

<em>1. A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin; 2. The radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball; 3. The volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

Step-by-step explanation:

If we expressed a number as:

\\ N = a * 10^{b} (1)

Where

\\ \frac{1}{\sqrt{10}} \leq a < \sqrt{10} (2)

or

\\ 1 \leq a < 10 (3)

Then, <em>b</em> represents the <em>order of magnitude </em>of such a number (<em>Order of magnitude (2020), </em>in Wikipedia).

The order of magnitude can be defined as "...the smallest power of ten needed to represent a quantity" (Weisstein, Eric W. "Order of Magnitude". From MathWorld--A Wolfram Web Resource).

Having gathered all this information, we can proceed as follows:

<h3>First case</h3>

The<em> La Plata river dolphin</em> weighs between 30 and 50kg and the sperm whale weighs between 35,000 and 40,000kg.

Then, considering (1) and (3) to express the dolphin and whale's weight (since in this way the order of magnitude is the same as the exponent part in the <em>scientific notation</em>):

\\ 30kg \leq Dolphin_{weight} \leq 50kg

\\ 3*10^{1}kg \leq Dolphin_{weight} \leq 5*10^{1}kg

\\ 35000kg \leq Whale_{weight} \leq 40000kg

\\ 3.5*10^{4}kg \leq Whale_{weight} \leq 4.0*10^{4}kg

Since the range for the weights are in the same order of magnitude for both dolphin and whale (considering the definition above):

\\ Dolphin_{weight} = 10^{1}\;(order\;of\;magnitude=1)

\\ Whale_{weight} = 10^{4}\;(order\;of\;magnitude=4)

Then

\\ \frac{Whale_{weight} = 10^{4}}{Dolphin_{weight} = 10^{1}}

\\ \frac{Whale_{weight}}{Dolphin_{weight}} = \frac{10^{4}}{10^{1}}

\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{4-1}

\\ \frac{Whale_{weight}}{Dolphin_{weight}} = 10^{3}

Thus

<em>A sperm whale is </em><em>3</em><em> </em><em>orders of magnitude</em><em> heavier than a La Plata river dolphin.</em>

<h3>Second case</h3>

Following the same reasoning, we can conclude that <em>the radius of the larger ball is </em><em>one (1) order of magnitude</em><em> bigger than the radius of the smaller ball:</em>

\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = \frac{10^{1}}{10^{0}}

\\ \frac{Larger\;ball_{radius}}{Smaller\;ball_{radius}} = 10^{1-0} = 10^{1}

<h3>Third case</h3>

For this case, we need to calculate <em>the volume of a sphere</em> for both radii (1cm and 10cm).

The volume of a sphere is

\\ V_{sphere} = \frac{4}{3}*\pi*R^{3}

Then, the volume of the <em>ball of radius 1cm</em> is:

\\ V_{radius=1} = \frac{4}{3}*\pi*(1cm)^{3}

\\ V_{radius=1} \approx 4.19*10^{0}cm^{3}

And, the volume of the <em>ball of radius 10cm</em> is:

\\ V_{radius=10} = \frac{4}{3}*\pi*(10cm)^{3}

\\ V_{radius=10} \approx 4.19*10^{3}cm^{3}

Thus

\\ \frac{10^{3}}{10^{0}} = 10^{3}

As a result, <em>the volume of the larger ball is </em><em>3 orders of magnitude</em><em> bigger than the volume of the smaller ball</em>.

4 0
3 years ago
How do you solve 6x + 8= 50
Marina CMI [18]
First start by subtracting:
50-8=42
the new equation is:
6x=42
then divide:
42/6=7
So the answer is:
x=7

Hope this helps!! :D

6 0
3 years ago
Read 2 more answers
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