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tatuchka [14]
3 years ago
12

PLEASE ANSWER !! you went to Olive Garden with your family. The bill was $64.25. You left a 16% tip. How much money was your bil

l including the tip?
Mathematics
1 answer:
irina [24]3 years ago
8 0

Answer:

$74.53

Step-by-step explanation:

16%=0.16

0.16*64.25+64.25

=(0.16+1)*64.25

=$74.53

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I will give Brainliest AND a Cookie!
CaHeK987 [17]

Answer:

5

Step-by-step explanation:

\sqrt{25} =5 This means that it has the highest value

4 0
3 years ago
Read 2 more answers
A sector of a circle has a central angle of 100 degrees. If the area of the sector is 50pi, what is the radius of the circle
MrMuchimi

The radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is <u>6√5 units</u>.

An area of a circle with two radii and an arc is referred to as a sector. The minor sector, which is the smaller section of the circle, and the major sector, which is the bigger component of the circle, are the two sectors that make up a circle.

Area of a Sector of a Circle = (θ/360°) πr², where r is the radius of the circle and θ is the sector angle, in degrees, that the arc at the center subtends.

In the question, we are asked to find the radius of the circle in which a sector has a central angle of 100° and the area of the sector is 50π.

From the given information, the area of the sector = 50π, the central angle, θ = 100°, and the radius r is unknown.

Substituting the known values in the formula Area of a Sector of a Circle = (θ/360°) πr², we get:

50π = (100°/360°) πr²,

or, r² = 50*360°/100° = 180,

or, r = √180 = 6√5.

Thus, the radius of the circle having the area of the sector 50π, and the central angle of the radius as 100° is <u>6√5 units</u>.

Learn more about the area of a sector at

brainly.com/question/22972014

#SPJ4

8 0
1 year ago
How long will it take for an investment of $2000 to double in value if the interest rate is 7.25%
lesya692 [45]

Answer:

t = ln2/0.075

t = 9.24 years.

hope this helps

3 0
3 years ago
The length of a rectangle is 6 more than twice the width. if the area is 40 cm^2, find the length and breadth of the rectangle
ra1l [238]

Answer: 3.217 & 12.434

Step-by-step explanation:

If we use <em>w</em> to represent the width, the length will be 6 more than 2 times w.

Hence, the length is 2w+6.

The area of a rectangle would be its length times its width, so let's make an equation to represent it's area.

A=w(2w+6)

We can also substitute 40 in for A as it's given in the question.

40 = w(2w+6)

Distributing <em>w</em> by multiplying it by both terms in the parentheses, we get

40 = 2w^2+6w

We can make the equation simpler by dividing both sides by 2.

20 = w^2+3w

Subtracting both sides by 20 will make the left-hand side 0.

0=w^2+3w-20

Now that we have put this <em>quadratic equation</em> into standard form (ax²+bx+c), we can find its solutions using the quadratic formula.

For reference, the quadratic formula is

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, a is 1, b is 3, and c is -20.

Substituting, we get

w=\frac{-3\pm\sqrt{3^2-4(1)(-20)}}{2(1)}

w= \frac{-3\pm\sqrt{9+80}}{2}

w=\frac{-3+\sqrt{89}}{2}\hspace{0.1cm}or\hspace{0.1cm}\frac{-3-\sqrt{89}}{2}

Since the second solution results in a negative number, it cannot be the length of w.

w=\frac{-3+\sqrt{89}}{2}\approx3.217

The width/breadth of the rectangle is 3.217 cm.

To calculate the length, let's substitute the width into the expression for the length:

l=2(3.217)+6

l=12.434

The length of this rectangle is 12.434 cm.

6 0
1 year ago
The time to complete the construction of a soapbox derby car is normally distributed with a mean of three hours and a standard d
TEA [102]

Answer:

The probability that it would take more than four hours to construct a soapbox derby car = 0.1587 or 15.87\%

Step-by-step explanation:

Given -

Mean (\nu )  = 3 hours

Standard deviation (\sigma  ) = 1 hours

Let X be the no of hours to construct a soapbox derby car

the probability that it would take more than four hours to construct a soapbox derby car =

P(X > 4)  = P(\frac{X - \nu }{\sigma}> \frac{4 - 3 }{1})

                = P(Z > 1)                   Put (Z = \frac{X - \nu }{\sigma})

                 =  1 -  P(Z <  1)            

                 =  1 - .8413                    Using z table

                  = 0.1587

3 0
3 years ago
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