Keegan had 3.25 pounds of flour. After making bread, he had 1.75 pounds of flour left over. i know its 1.5 but whats the Equatio
1 answer:
You might be interested in
Problem 17, part A
i = simple interest = 900 dolars
p = principle = 1500 dollars
r = interest rate = 0.03 (decimal form of 3%)
t = time in years = unknown (leave it as t for now)
Plug in those values mentioned above and solve for t.
Simple interest formula
i = p*r*t
900 = 1500*0.03*t
900 = 45*t
900/45 = 45*t/45
20 = t
t = 20
Answer: 20 years
=============================================
Problem 17, part B
p = 1500
r = 0.03
t = 5 years
A = p+p*r*t
A = 1500+1500*0.03*5
A = 1500+225
A = 1725
Answer: 1725 dollars
=============================================
Problem 17, part C
Factor out the GCF p, then divide both sides by 1+rt
A = p+p*r*t
A = p*1+p*r*t
A = p*(1+rt)
A/(1+rt) = p*(1+rt)/(1+rt)
A/(1+rt) = p
p = A/(1+rt)
Answer: p = A/(1+rt)
The right side is the fraction of A all over the quantity (1+rt) which may be more readable if written like so
If you're going to write it in the way p = A/(1+rt) then don't forget to use parenthesis.
i = simple interest = 900 dolars
p = principle = 1500 dollars
r = interest rate = 0.03 (decimal form of 3%)
t = time in years = unknown (leave it as t for now)
Plug in those values mentioned above and solve for t.
Simple interest formula
i = p*r*t
900 = 1500*0.03*t
900 = 45*t
900/45 = 45*t/45
20 = t
t = 20
Answer: 20 years
=============================================
Problem 17, part B
p = 1500
r = 0.03
t = 5 years
A = p+p*r*t
A = 1500+1500*0.03*5
A = 1500+225
A = 1725
Answer: 1725 dollars
=============================================
Problem 17, part C
Factor out the GCF p, then divide both sides by 1+rt
A = p+p*r*t
A = p*1+p*r*t
A = p*(1+rt)
A/(1+rt) = p*(1+rt)/(1+rt)
A/(1+rt) = p
p = A/(1+rt)
Answer: p = A/(1+rt)
The right side is the fraction of A all over the quantity (1+rt) which may be more readable if written like so
If you're going to write it in the way p = A/(1+rt) then don't forget to use parenthesis.