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olga nikolaevna [1]
3 years ago
15

Solve the quadratic equation 12x^2 - 288 = 0 using the square root method.

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

C) x = ± 4

Step-by-step explanation:

12x² - 288 = 0

  • Add 288 on both sides. Anything plus zero gives itself.

12x ² = 288

  • Divide both side by 12

\small \sf \: x {}^{2}  =  \frac{288}{12} \\

  • Divide 288 by 12 to get 24

\small \sf  x {}^{2} =  \frac{ \cancel{288 }}{ \cancel{12}} \\

x² = 24

  • Taking square root of each side and remember to use positive and negative roots

\small \sf \:  \sqrt{x {}^{2} }  =    ± \sqrt{ 24}

\small \sf \:  x_1, _2 =   ± \sqrt{ 24}

\small \sf \: x_1, _2 =   ± 4.899

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Math helpppp i willl be marking brainliest
Nostrana [21]
1/16
Probability of 4 = 1/8
Probability of odd number. = 3/6

So probability of 4 and odd number=1/8*3/6
=1/16

Hope this helps!
6 0
3 years ago
One angle measure in an acute triangle is 38°. What could the measure of one of the other angles be?
Snezhnost [94]

Answer:

ex.: 71 (see explanation)

Step-by-step explanation:

The answers on this could vary. An acute angle is an angle less than 90 degrees. However, you also have to remember that a triangle adds up to 180 degrees, so the angle cannot be so small that the third angle would be over 90. For my answer, I subtracted 38 from 180 (the whole triangle) and then divided by 2.

I hope this helps.

4 0
3 years ago
If 5-y^2=x^2 then find d^2y/dx^2 at the point (2, 1) in simplest form. ​
ratelena [41]

Answer:

y"(2, 1) = -5

Step-by-step explanation:

Step 1: Define implicit differentiation

5 - y² = x²

Step 2: Find dy/dx

  1. Take implicit differentiation: -2yy' = 2x
  2. Isolate y': y' = 2x/-2y
  3. Isolate y': y' = -x/y

Step 3: Find d²y/dx²

  1. Quotient Rule: y'' = [y(-1) - y'(-x)] / y²
  2. Substitute y': y" = [-y - (-x/y)(-x)] / y²
  3. Simplify: y" = [-y - x²/y] / y²
  4. Multiply top/bottom by y: y" = (-y² - x²) / y³
  5. Factor negative: y" = -(y² + x²) / y³

Step 4: Substitute and Evaluate

y"(2, 1) = -(1² + 2²) / 1³

y"(2, 1) = -(1 + 4) / 1

y"(2, 1) = -5/1

y"(2, 1) = -5

3 0
3 years ago
Solv for x for all of these 1. 3x+6=21 2. 33=7x-9 3. 28=7+x need to know now please help !!!!!!
-Dominant- [34]

Answer:

<h3>\boxed{ \sf{ \bold{1.  \:  \: \: x = 5}}}</h3>

\boxed{ \sf{ \bold{2. \:  \: x = 6}}}

\boxed{ \bold{ \sf{3. \:  \: x = 21}}}

Step-by-step explanation:

1. \sf{3x + 6 = 21}

Move constant to right hand side and change its sign

⇒\sf{3x = 21 - 6}

Subtract 6 from 21

⇒\sf{3x = 15}

Divide both sides of the equation by 3

⇒\sf{ \frac{3x}{3}  =  \frac{15}{3} }

Calculate

⇒\sf{x = 5}

--------------------------------------------------------

2. \sf{33  = 7x - 9 }

Swap the sides of the equation

⇒\sf{7x - 9 = 33}

Move constant to right hand side and change it's sign

⇒\sf{7x = 33 + 9}

Add the numbers

⇒\sf{7x = 42}

Divide both sides of the equation by 7

⇒\sf{ \frac{7x}{7}  =  \frac{42}{7} }

Calculate

⇒\sf{x = 6}

---------------------------------------------------------

3. \sf{28 = 7 + x}

Swap the sides of the equation

⇒\sf{7 + x = 28}

Move constant to right hand side and change it's sign

⇒\sf{x = 28 - 7}

Subtract 7 from 28

⇒\sf{x = 21}

Hope I helped!

Best regards!!

7 0
3 years ago
Need help asap mathematics
labwork [276]

Answer:

Step-by-step explanation:

Domain={-3,-2,1,2}

Range={3,5}

Yes the relation is a function.

7 0
3 years ago
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