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olga nikolaevna [1]
3 years ago
15

Solve the quadratic equation 12x^2 - 288 = 0 using the square root method.

Mathematics
1 answer:
krok68 [10]3 years ago
4 0

Answer:

C) x = ± 4

Step-by-step explanation:

12x² - 288 = 0

  • Add 288 on both sides. Anything plus zero gives itself.

12x ² = 288

  • Divide both side by 12

\small \sf \: x {}^{2}  =  \frac{288}{12} \\

  • Divide 288 by 12 to get 24

\small \sf  x {}^{2} =  \frac{ \cancel{288 }}{ \cancel{12}} \\

x² = 24

  • Taking square root of each side and remember to use positive and negative roots

\small \sf \:  \sqrt{x {}^{2} }  =    ± \sqrt{ 24}

\small \sf \:  x_1, _2 =   ± \sqrt{ 24}

\small \sf \: x_1, _2 =   ± 4.899

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The slope is 7/5 and the equation of the line is 5y - 7x = 0 if the points ​(10​,14​) and ​(35​,49​) form a proportional relationship.

<h3>What is the slope?</h3>

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

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From the above formula, we can find the slope of the line:

m = (49-14)/(35-10)

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The equation will be:

y = 7x/5 + c

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Plug (10, 14) in the equation to find the value of c

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