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sergey [27]
2 years ago
14

The short sides of a rectangle are 2 inches. The long sides of the same rectangle are three less than an unknown number of inche

s.
Two students are told that the perimeter of this rectangle is at least 30 inches. The first student says, "The length of the long side must be at least 13 inches". The second student says, "The unknown number must be at least 10 inches". Which of the following statements is true?

The first student is correct.
The second student is correct.
Both students are correct.
Neither student is correct.
Mathematics
2 answers:
anyanavicka [17]2 years ago
8 0
First student is correct. explanation: 2+2+13+13=30, if the perimeter has to be at least 30 13 is the option that adds up to it.
Delicious77 [7]2 years ago
5 0
The first student is correct because 30-4=26
26 divided by 2=13 hope this helps :)
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6300 and 530,<br> 3 and 2 underlined <br> Compare value<br><br> The value 3 in____ is _____times
topjm [15]
Basically when reading the value of a digit we start from the right.
Digits from the right to the left are named as follows:
units......>no zeros/digits after them
tens......> 1 zero/digit after the digit
hundreds.......> 2 zeros/digits after the digit
thousands......> 3 zeros/digits after the digit
ten thousands.......> 4 zeros/digits after the digit
hundred thousands.........> 5 zeros/digits after the digit
million........> 6 zeros/digits after the digit

Applying this on the above mentioned numbers, we will find that the 3 represents the hundreds (300) in 6300 while it represent the tens (30) in 530.

The question is to find the difference between the two, which means we will subtract them:
difference = 300 - 30 = 270

<span>The value 3 in 6300 is 270 times the value of 3 in 530
</span>
5 0
3 years ago
What is the value of the expression (30 - 6b) when b is 3.5
geniusboy [140]

Answer:

9

Step-by-step explanation:

30 - 6(3.5)

30 - 21

9

6 0
2 years ago
Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x
Serggg [28]

I assume C has counterclockwise orientation when viewed from above.

By Stokes' theorem,

\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

so we first compute the curl:

\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k

\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k

Then parameterize S by

\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k

where the z-component is obtained from

1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v

with 0\le u\le\dfrac\pi2 and 0\le v\le\dfrac\pi2.

Take the normal vector to S to be

\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k

Then the line integral is equal in value to the surface integral,

\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv

=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}

6 0
3 years ago
Anyone know how to do it
Morgarella [4.7K]

Answer:

Surface area of cube = 6x²

surface area of cube = surface area of sphere

it means that 6x²=4πr²

x²=

\frac{4\pi {r}^{2}  }{6}  =  \frac{4 \pi9}{6}  =  \frac{4\pi3}{2}  = 6\pi

x =   \sqrt{6\pi}

\sqrt{6\pi}  =  \sqrt{k\pi}

6\pi = \pi \: k

k = 6

4 0
2 years ago
Greatest common factor <br>3a^3+9a^2​
BaLLatris [955]

Answer:

27A+81A =108

Step-by-step explanation:

7 0
3 years ago
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