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Jet001 [13]
3 years ago
11

Square root of 50 + square root of 2

Mathematics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

8.48528137424

Step-by-step explanation:

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Let d be the number of dollars you spent on gas and let g be the number of gallons you purchased. Which expression represents th
Marianna [84]

Answer:

The expression represents the price you paid per gallon is:

  • Price paid per gallon = \frac{d}{g}

Step-by-step explanation:

To identify the expression is right, I'll show you with an example: suppose that you paid $56 buying 7 gallons of gas, now you can replace those values in the expression I gave you:

  • Price paid per gallon = \frac{d}{g}
  • Price paid per gallon = \frac{56}{7}
  • Price paid per gallon = 8

And you can check this value by multiplying the price paid by the gallon and the number of gallons, which you obtain the number of dollars you spent:

  • <u>Number of dollars (d) = 8 * $7 = $56 </u>
3 0
3 years ago
Brent rode his bicycle 4 miles on Saturday. There are 1,760 yards in a mile. How many yards did Brent ride on Saturday? Explain
Jet001 [13]

Answer:

  • 7040 yards
  • zeros are place holders

Step-by-step explanation:

Each mile is 1760 yards, so 4 of them is ...

  4 × 1760 yards = 7040 yards

__

This number is written as a decimal number in a "place value" system, so the position of the digit in the number tells its value.

In order for the 7 to indicate 7 thousand, it needs to be in the "thousands" place in the number. The 0s in the hundreds and units places are called "place holders" because they ensure the other digits appear in their proper places in the number.

__

If it were written in Roman Numerals, it would be \overline{\text{V}}\text{MMXL}. In this system, the letter tells its value (and "place" comes into account in XL, which means X is subtracted from L). The system of Roman Numerals has no zeros, and doesn't need them.

3 0
3 years ago
If jake has 2 apples and steve took 1 away hiw many apples does he have left​
kirill [66]

Answer:

He clearly has 1 apple left. Because if we started with 2 and then one was taken away you would do 2-1=1

Step-by-step explanation:

2 apples

2-1

2-1=1

1 apple

7 0
4 years ago
Read 2 more answers
SUppose the total cost C(x) to manufacture a quantity x of insecticide (in hundreds of liters) is given by
Hitman42 [59]

Answer:

a) C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty).

b) C(x) decreases in (8\,s, 10\,s).

Step-by-step explanation:

Let C(x) = x^{3}-27\cdot x^{2}+240\cdot x +850, where x is the quantity of insecticide, measured in hundreds of liters, and C(x) is the total manufacturing cost as a function of the quantity of the insecticide, measured in US dollars. A possible approach to determine which regions of C(x) are decreasing and increasing by means of the first derivative and graphing tools. The first derivative of the function is:

C'(x) = 3\cdot x^{2}-54\cdot x+240 (1)

Please notice that regions where C(x) is increasing has C'(x) > 0, whereas C'(x) < 0 when C(x) < 0.

We notice that C(x) is increasing in two regions: (i) (+\infty, 8\,s) and (ii) (10\,s,+\infty). Besides, C(x) decreases in (8\,s, 10\,s).

6 0
3 years ago
Suppose that P(n) is a propositional function. Determine for which nonnegative integers n the statement P(n) must be true if a)
wel

Solution :

a). $P(0)$ is true

Then ,$P(0+2)=P(2)$ is true.

         $P(2+2)=P(4)$ is true

          $P(4+2)=P(6)$ is true.

Therefore, we see that $P(n)$ is true for all the even integers : $\{0, 2,4,6,...\}$

b). $P(0)$ is true

Then ,$P(0+3)=P(3)$ is true.

         $P(3+3)=P(6)$ is true

          $P(6+3)=P(9)$ is true.

Therefore, we see that $P(n)$ is true for all the multiples of 3 : $\{0, 3,6,9,12,...\}$

c). $P(0)$ and $P(1)$ is true, then $P(0+2)=P(2)$ is true

$P(1)$ and $P(2)$ is true, then $P(1+2)=P(3)$ is true.

$P(2)$ and $P(3)$ is true, then $P(2+2)=P(4)$ is true.

So, we observe that  $P(n)$ is true for all the non- negative integers : $\{0, 1,2,3,4,5,6,...\}$.

d). $P(0)$ is true,

   So, $P(0+2)$ and $P(0+3)$ is true or $P(2)$ and $P(3)$ is true.

   Now,   $P(2)$ is true.

Again, $P(2+2)$ and $P(2+3)$ is true or $P(4)$ and $P(5)$ is true.

   Now, $P(3)$ is true.

Again, $P(3+2)$ and $P(3+3)$ is true or $P(5)$ and $P(6)$ is true.

Thus,

$P(n)$ is true for all the non- negative integers except 1 : $\{0, 2,3,4,5,6,...\}$.

3 0
3 years ago
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