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Alisiya [41]
3 years ago
5

What are the steps needed to solve ⅘ ÷ ⅕ ?

Mathematics
1 answer:
NemiM [27]3 years ago
8 0
“Keep, Change, Flip” so keep the 4/5 then change the •|• and then flip the last fraction to 5/1 and then multiply the fractions like normal
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The numerator and denominator of a fraction are in the ratio of 3 to 5. If the numerator and denominator are both increased by 2
butalik [34]

Answer:

The correct answer is A) 5n = 3d and 3n + 6 = 2d + 4

Step-by-step explanation:

hope this is right...

6 0
3 years ago
Richard wants to find out his current grade in math dass after taking five quizzes. Which measure of center
Salsk061 [2.6K]

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question does not seem complete, from what i know it sounds like he should add up the test scores and divide it by five, that will give him his average which should be his grade, please update question if possible

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7 0
3 years ago
F−1(−2) = <br><br> f(−4) = <br><br> f(f−1(−2)) =
Sauron [17]

need more information

7 0
3 years ago
Read 2 more answers
Solve the equation. 1.25 =0.75+r
Eduardwww [97]

Answer:

0.50

Step-by-step explanation:

Do the opposite of addition

So 1.25 - 0.75

6 0
3 years ago
Read 2 more answers
Find the absolute maximum and minimum values of the function, subject to the given constraints. k(x,y)=−x2−y2 4x 4y; 0≤x≤3, y≥0,
grigory [225]

For function k(x, y) = -x² - y² + 4x + 4y,

the absolute minimum is 0 and the absolute maximum is 6

For given question,

We have been given a function k(x, y) = -x² - y² + 4x + 4y

We need to find the absolute maximum and minimum values of the function, subject to the constraints 0 ≤ x ≤ 3, y ≥ 0, and x + y ≤ 6

First we find the partial derivative of function k(x, y) with respect to x.

⇒ k_x=-2x+4

Now, we find the partial derivative of function k(x, y) with respect to y.

\Rightarrow k_y=-2y+4

To find the critical point:

consider    k_x=0     and      k_y=0

⇒       -2x + 4 = 0     and    -2y + 4 = 0

⇒          x = 2            and       y = 2

This means, the critical point of function is (2, 2)

We have been given constraints 0 ≤ x ≤ 3, y ≥ 0, and x + y ≤ 6

Consider k(0, 0)

⇒ k(0, 0) = -0² - 0² + 4(0) + 4(0)

⇒ k(0, 0) = 0

Consider k(3, 3)

⇒ k(3, 3) = -3² - 3² + 4(3) + 4(3)

⇒ k(3, 3) = -9 - 9 + 12 + 12

⇒ k(3, 3) = -18 + 24

⇒ k(3, 3) = 6

Therefore, for function k(x, y) = -x² - y² + 4x + 4y,

the absolute minimum is 0 and the absolute maximum is 6

Learn more about the absolute maximum and absolute minimum values of the function here:

brainly.com/question/16270755

#SPJ4

4 0
1 year ago
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