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IgorLugansk [536]

2 years ago

12

pls help ! If I have 17 moles of gas at a temperature of 67°C, and a pressure of 5.34 atmospheres, what is the volume of the gas

? Write the generic equation (equation with variables only) for this problem.

1 answer:

sleet_krkn [62]2 years ago

3 0

We don't have to find the volume .We have to write the formula to find

$\\ \bull\tt\longmapsto PV=nRT$

P=Pressure
V=Volume
n=no of moles
R=Universal Gas constant
T=Temperature

$\\ \bull\tt\longmapsto V=\dfrac{nRT}{P}$

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PSYCHO15rus [73]

Answer: Oxygen usually forms two covalent bonds or a covalent double bond.

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A covalent bond is formed by the sharing of 2 electrons, 1 electron from each of the atoms sharing their electrons.

The number of bonds that each element can form depends on the number of valence (outermost) electrons it contains. Oxygen has 6 electrons in its valence shell and needs 2 more electrons thereby forming a double bond.

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3 years ago

Ten pints of 15 % salt solution are mixed with 15 pints of 10 % salt solution. What is the

sergij07 [2.7K]

$Concentration\ rate=\frac{mass\ of\ product}{mass\ of\ substance}*100\%\\\\
15\%=\frac{m_1}{ms_1}*100\%\\ms_1=10pints\\
15\%=\frac{m_1}{10}*100\%\\
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m_1=\frac{150}{100}=1,5pints\\\\
10\%=\frac{m_2}{15}*100\%\\
0,1=\frac{m_2}{15}\ \ |*15\\
1,5=m_2\\
Resulting\ solution:\\
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7 0

2 years ago

How would adding the catalyst nitrogen monoxide (NO) affect this reaction?

marin [14]

<u>Answer:</u> The correct answer is Option A.

<u>Explanation:</u>

A catalyst is defined as the substance which increases the rate of the reaction without actually participating in the reaction.

This substance decreases the activation energy of the reactants, so as to proceed the reaction at a faster rate by increasing their effective collisions.

It does not affect the concentration of the reactants.

For the given reaction:

$2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)$

If we add NO, which is acting as a catalyst will increase the rate of the reaction to produce the products which is $SO_3$

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5 0

3 years ago

Read 2 more answers

A student reduces the temperature of a 300 cm3 balloon from 60°c to 30°

FromTheMoon [43]

We can use the ideal gas equation which is expressed as PV = nRT. At a constant pressure and number of moles of the gas the ratio T/V is equal to some constant. At another set of condition of temperature, the constant is still the same. Calculations are as follows:

T1 / V1 = T2 / V2

V2 = T2 x V1 / T1

V2 = 303.15 x 300 / 333.15

<span>V2 = 272.99 cm³</span>

7 0

3 years ago

3. Given the following equation:

miskamm [114]

Answer:

4.767 grams of KCl are produced from 2.50 g of K and excess Cl2

Explanation:

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So, 2 moles of K produces 2 moles of KCL

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4 0

2 years ago