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VashaNatasha [74]
3 years ago
10

Can somebody plz help answer these true or false questions correctly thanks! (Only if u for sure know them) :)

Chemistry
1 answer:
asambeis [7]3 years ago
7 0

Answer:

1. False

2. True

3. False

4. True

5. True

Explanation:

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A 29.0-g sample of water at 290. K is mixed with 51.0 g water at 300. K. Calculate the final temperature of the mixture assuming
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This stadium can hold 100,000, or 1 x 10^5, people. The number of atoms in a grain of iron is about 1 x 10^18. Would you need 1 
polet [3.4K]
<h3>Answer:</h3>

1 x 10^13 stadiums

<h3>Explanation:</h3>

From the question;

1 x 10^5 people can fill 1 stadium

We are given,  1 x 10^18 atoms of iron

We are required to determine the number of stadiums that  1 x 10^18 atoms of iron would occupy.

We are going to assume that a stadium would occupy a number of atoms equivalent to the number of people.

Therefore;

One stadium =  1 x 10^5 atoms

Then, to find the number of stadiums that will be occupied by  1 x 10^18 atoms;

No. of stadiums = Total number of atoms ÷ Atoms in a single stadium

                           =  1 x 10^18 atoms ÷  1 x 10^5 atoms

                          =  1 x 10^13 stadiums

Therefore,  1 x 10^18 atoms of iron would occupy  1 x 10^13 stadiums

7 0
2 years ago
Consider the balanced equation below. 4NH3 + 3O2 --&gt; 2N2 + 6H2O What is the mole ratio of NH3 to N2?
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The balanced equation given is:
4NH3 + 3O2 .....> 2N2 + 6H2O

From this equation, we can note that 4 moles of NH3 are required to produce 2 moles of N2.

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3 years ago
A 0.580 g sample of a compound containing only carbon and hydrogen contains 0.480 g of carbon and 0.100 g of hydrogen. At STP, 3
Sati [7]

Answer:

Molecular formula for the gas is: C₄H₁₀

Explanation:

Let's propose the Ideal Gases Law to determine the moles of gas, that contains 0.087 g

At STP → 1 atm and 273.15K

1 atm . 0.0336 L = n . 0.082 . 273.15 K

n = (1 atm . 0.0336 L) / (0.082 . 273.15 K)

n = 1.500 × 10⁻³ moles

Molar mass of gas = 0.087 g / 1.500 × 10⁻³ moles = 58 g/m

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If 0.580 g of gas has ____ 0.480 g of C _____ 0.100 g of C

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7 0
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