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777dan777 [17]
3 years ago
8

hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that w

ould be really appreciated!!

Mathematics
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

\frac{-5 \pm \sqrt{13} }{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}<u />

<u />

<u>Step 2: Evaluate</u>

  1. Evaluate Exponents:                    \frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}
  2. Evaluate Multiplication:               \frac{-5 \pm \sqrt{25-12} }{6}
  3. Evaluate Subtraction:                  \frac{-5 \pm \sqrt{13} }{6}
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cricket20 [7]
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