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3 years ago

8

hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that w

ould be really appreciated!!

1 answer:

GuDViN [60]3 years ago

8 0

Answer:

$\frac{-5 \pm \sqrt{13} }{6}$

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

<u /> $\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}$ <u />

<u />

<u>Step 2: Evaluate</u>

Evaluate Exponents: $\frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}$
Evaluate Multiplication: $\frac{-5 \pm \sqrt{25-12} }{6}$
Evaluate Subtraction: $\frac{-5 \pm \sqrt{13} }{6}$

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Janie receives an allowance of $ 3 $3dollar sign, 3 per week. In addition, she can earn $ 2 $2dollar sign, 2 for each chore she

Gnesinka [82]

Hello Dafnemlp47vj7

The inequality for one week would be <u><em>13 = 2c + 3 </em></u>

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3 years ago

Describe how to find all the points on a baseball field that are equidistant from second base and third base

BlackZzzverrR [31]

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8 0

3 years ago

Help me with this please.

Ira Lisetskai [31]

Answer:

JL = 78

Step-by-step explanation:

MN is a midsegment. Based on the midsegment theorem,

MN = ½(JL)

MN = 5x - 16

JL = 4x + 34

Plug in the value

5x - 16 = ½(4x + 34)

5x - 16 = ½*4x + ½*34

5x - 16 = 2x + 17

Collect like terms

5x - 2x = 16 + 17

3x = 33

Divide both sides by 3

x = 11

✔️JL = 4x + 34

Plug in the value of x

JL = 4(11) + 34

JL = 44 + 34

JL = 78

5 0

3 years ago

ANSWER PLZ QUICK AND FAST

Digiron [165]

I believe it is C because I counted the dots in the shaded region.

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3 0

3 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by:

$t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96$

The margin of error for the proportion interval is given by this formula:

$ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$ (a)

And on this case we have that $ME =\pm 0.01$ and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}$ (b)

And replacing into equation (b) the values from part a we got:

$n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56$

And rounded up we have that n=6147

5 0

4 years ago