Question

hi i'm really struggling with this and its due later today! If someone could show the work of how to do it and the answer that would be really appreciated!!

Answer 1

Answer:

$\frac{-5 \pm \sqrt{13} }{6}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Step-by-step explanation:

Step 1: Define

$\frac{-5 \pm \sqrt{5^2-4(3)(1)} }{2(3)}$

Step 2: Evaluate

1. Evaluate Exponents:                    $\frac{-5 \pm \sqrt{25-4(3)(1)} }{2(3)}$
2. Evaluate Multiplication:               $\frac{-5 \pm \sqrt{25-12} }{6}$
3. Evaluate Subtraction:                  $\frac{-5 \pm \sqrt{13} }{6}$