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Lerok [7]
3 years ago
14

Jasmine is doing an experiment to see how much temperature change occurs when three different substances are heated. Between the

three conditions, she must control (keep the same) all of the following EXCEPT:​
Chemistry
1 answer:
Reptile [31]3 years ago
5 0

Answer:

SUBSTANCES

Explanation:

According to this question, Jasmine is conducting an experiment in order to see how much temperature change occurs when three different substances are heated. Based on this experiment, the INDEPENDENT VARIABLE, which is the variable that is changed or manipulated is SUBSTANCES.

A controlled experiment is an experiment where all other variables except the INDEPENDENT VARIABLE is kept the same or unchanged. The independent variable is the only variable allowed to change, which in this case is the SUBSTANCES USED.

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7 0
3 years ago
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Group I element are very active.give reason​
RUDIKE [14]

Answer:

wat

Explanation:

7 0
3 years ago
Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0
3 years ago
What is a scientific word for baking soda​
igor_vitrenko [27]

Sodium bicarbonate is commonly known as baking soda. The scientific name is NaHCO3. Baking soda is an alkaline compound found in crystalline form in nature.

Hope this helped

Brainliest is appreciated

Good luck

~ Emmy

5 0
3 years ago
PLEASE HELP<br> Which is a true of a molecule?<br> Quesion 3 <br> PLEASE HELP
insens350 [35]
The last one. A bond of two or more of the same element.
5 0
2 years ago
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