(NH₄)₂S
%N= 41.18%
%H =11.76%
%S=47.06%
Mg(NO₃)₂
%Mg=32.43%
%N=18.92%
%O=(64.86%
<h3>Further explanation</h3>
Given
(NH₄)₂S
Mg(NO₃)₂
Required
The percent composition
Solution
(NH₄)₂S MW=68 g/mol
%N=2. Ar N / MW (NH₄)₂S x 100%
%N= (2.14/68) x 100% = 41.18%
%H =(8.1/68) x 100%=11.76%
%S=(32/68)x 100%=47.06%
Mg(NO₃)₂ MW=148 g/mol
%Mg=(2.24/148)x100%=32.43%
%N=(2.14/148)x100%=18.92%
%O=(6.16/148)x100%=64.86%
Answer:
Check the explanation
Explanation:
Taking a look at the image, I have shown only the energy levels and not the proper curves, because we just need to calculate the energy differences.
Here, S2 denotes a ground state molecule while S2* denotes an excited state molecule
The energy D1, required for dissociation of excited state molecule to 2 ground state atoms is -ve, which means no energy is supplied, rather energy is emitted by this spontaneous dissociation.
Answer: Order of the species in their decreasing oxidizing agent ability is
Explanation: Oxidizing agent is defined as the agent which helps the other element to get oxidized and it itself gets reduced. These agents should have a positive value of reduction potentials. More is the positive value, best is the oxidizing agent.
Reducing agents are defined as the agents which helps the other element to get reduced and itself gets oxidized. These agents have a negative value of reduction potentials. The more the negative value, best is the reducing agent.
Reduction potentials of the following elements are:
From the given reduction potentials, the best oxidizing agent is and the best reducing agent is
Order in the decreasing oxidizing agent ability of the species is
Answer:
101.98 L
Explanation:
Ideal Gas Law PV = n R T R = gas constant = .082057 L-atm/mol-K
6.35 (V) = 4 * .082057 * 1973
V = 101.98 L
Explanation:
Since, NaCl exists as and in solution. Therefore, Van't Hoff factor (i) will be equal to 2.
Now, we assume that there are "n" moles of NaCl in the given solution. And, we assume that there is 1 kg of solvent (water).
So,
0.264 =
n = 0.132
Also, moles of water will be calculated as follows.
Moles of water =
= 55.56 mol
Hence, mole fraction of NaCl is calculated as follows.
Mole fraction =
=
Hence, mole fraction of NaCl will be .
At , the vapor pressure will be calculated as follows.
71.9 - p = 18.98
p = 52.92 torr
Therefore, vapor pressure of the given solution is 52.92 torr.