Question

A 200 kg roller coaster car is located at the top of a hill where the height is 30 m. What is the velocity when it reaches the bottom of the hill?

Answer 1

Answer:

d- 24.2 m/s

Explanation:

i just answered on edge

Answer 2

Assuming there is not loss of energy due to frinction (which is an idealization), you can use the conservation of energy law in the form:


Mechanical energy at top = mechanical energy at bottom.


Mechanical energy at top = potential energy = m * g * h


Mechanical energy at bottom = kinetic energy = m * v^2 / 2


=> m *v^2 / 2 = m * g * h

=> v^2 / 2 = g * h

=> v ^2 = 2gh

=> v = √(2gh) = √(2 * 9.8 m/s^2 *30m) = 24.25 m/s


Answer: 24.25 m/s