Answer:
On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?
That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)
Step-by-step explanation:
Answer: 1/7
Step-by-step explanation:
7x=1
x=1/7
The area <em>A</em> of a trapezoid with height <em>h</em> and bases <em>b</em>₁ and <em>b</em>₂ is equal to the average of the bases times the height:
<em>A</em> = (<em>b</em>₁ + <em>b</em>₂) <em>h</em> / 2
We're given <em>A</em> = 864, <em>h</em> = 24, and one of the bases has length 30, so
864 = (<em>b</em>₁ + 30) 24 / 2
864 = (<em>b</em>₁ + 30) 12
864 = (<em>b</em>₁ + 30) 12
72 = <em>b</em>₁ + 30
<em>b</em>₁ = 42
In order to develop an equation, let's use the slope-intercept form of the linear equation:
Using the points (3, 13.5) and (5, 18.5) from the table, we have:
Subtracting the second and the first equation:
Now, finding the value of b:
So the equation that represents this table is y = 2.5x + 6
Looking at the options, the correct one is E (none of the above).
Answer:
1/12
Step-by-step explanation:
2/3=8/12
2x4=8
3x4=12
1/4=3/12
1x3=3
4x3=12
8/12+3/12=11/12
1-11/12= 1/12