Question

Whats the best answer

Answer 1

Answer:

$\displaystyle\sqrt[3]{2x}-6\sqrt[3]{x}$

Step-by-step explanation:

$7\sqrt[3]{2x}-3\sqrt[3]{16x}-3\sqrt[3]{8x}=7\sqrt[3]{2x}-3\sqrt[3]{8}\sqrt[3]{2x}-3\sqrt[3]{8}\sqrt[3]{x}\\\\=7\sqrt[3]{2x}-3\cdot 2\sqrt[3]{2x}-3\cdot 2\sqrt[3]{x}=(7-6)\sqrt[3]{2x}-6\sqrt[3]{x}\\\\=\sqrt[3]{2x}-6\sqrt[3]{x}$