Answer:
Step-by-step explanation:
Answer:
6.68% of students from this school earn scores that satisfy the admission requirement
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The local college includes a minimum score of 1954 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement
This is 1 subtracted by the pvalue of Z when X = 1954. So
has a pvalue of 0.9332
1 - 0.9332 = 0.0668
6.68% of students from this school earn scores that satisfy the admission requirement
The binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.
<h3>How to expand the power of a binomial</h3>
Herein we have the seventh power of a binomial, whose expanded form can be found by using the binomial theorem and Pascal's triangle. Hence, we find the following expression for the expanded form:
(2 · x + y)⁷
(2 · x)⁷ + 7 · (2 · x)⁶ · y + 21 · (2 · x)⁵ · y² + 35 · (2 · x)⁴ · y³ + 35 · (2 · x)³ · y⁴ + 21 · (2 · x)² · y⁵ + 7 · (2 · x) · y⁶ + y⁷
128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷
Then, the binomial (2 · x + y)⁷ in expanded form by 128 · x⁷ + 448 · x⁶ · y + 672 · x⁵ · y² + 560 · x⁴ · y³ + 280 · x³ · y⁴ + 84 · x² · y⁵ + 14 · x · y⁶ + y⁷.
To learn more on binomials: brainly.com/question/12249986
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Answer:
g(z + 1) = 3z + 2
Step-by-step explanation:
Let g(x) = 3x – 1
Find g(z +1)
g(z + 1) = 3*(z +1) - 1
g(z + 1) = 3z + 3 - 1
g(z + 1) = 3z + 2
6 one coin can fall on heads and tails and also stand straight up that’s 3 ways one coin can fall since you said 2 coins it’s 6 ways