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zaharov [31]
3 years ago
12

A bear can run up to 18.47 feet per second. How many feet could the bear run in 3.9 seconds? 720.33 feet 7,203.3 feet 72.033 fee

t 7.2033 feet
Mathematics
2 answers:
JulsSmile [24]3 years ago
8 0

Answer:

72.033 ft

Step-by-step explanation:

To find this, let us set up a fraction. Since 18.47 = 1 second, y = is 3.9 seconds. Let "y" be the variable.

\frac{18.47}{1}=\frac{y}{3.9}

Step 1: Switch sides

\frac{y}{3.9}=\frac{18.47}{1}

Step 2: Apply rule: \frac{a}{1}=a

\frac{y}{3.9}=18.47

Step 3: Multiply both sides by 3.9

\frac{3.9y}{3.9}=18.47\cdot \:3.9

Step 4: Simplify

y=72.033

The bear can run 72.033 feet in 3.9 seconds

DochEvi [55]3 years ago
7 0
72.033 feet is ur answerr
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From the information given, we are told to use the slope formula along with the coordinates of points A, B, C, and D to find the slope.

The slope of AB based on the information will be:

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2 years ago
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djyliett [7]

Answer:

The equation's result: 32,000 (Rounded)

Goal: Find the closest or equivalent result in another expression

Step-by-step explanation:

<h3>A)</h3>

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1 year ago
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ruslelena [56]
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3 years ago
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Hyun Woo is riding a ferris wheel. H t H(t) models his height (in m m) above the ground, t t seconds after the ride starts. Here
worty [1.4K]

Answer:

<u></u>

  • <u>53 seconds.</u>

Explanation:

The text and the model are garbled.

This is the question amended:

<em />

<em>Hyun Woo is riding a ferris wheel. H(t) models his height (in m) above the ground, t seconds after the ride starts. Here, t is entered in radians.</em>

<em>H(t) = -10 cos(2π/150 t)+10</em>

<em />

<em>When does Hyun Woo first reach a height of 16 m?</em>

<em />

<h2>Solution</h2>

<em />

When <em>Hyun Woo reaches a height of 16 m</em> the <em>model </em>states:

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<em />

Then you must find the lowest positive value of t that is a solution of the equation.

Solve the equation:

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