Answer:
x = 12
Step-by-step explanation:
<u>To find "x"</u>, we need to <u>isolate it</u>. This means move "x" to the left side, and everything else to the right side.
When moving a number, do its <u>reverse operation</u> to the entire equation.
x + 9 = 2x - 3
x - 2x + 9 = 2x - 2x - 3 Subtract 2x from both sides
-x + 9 = -3
-x + 9 - 9 = -3 - 9 Subtract 9 from both sides
-x = -12
-x/-1 = -12/-1 Divide both sides by -1 to get rid of the negatives
x = 12 Final answer
Check your answer. Split the equation for the left and right sides. Substitute "x" for the answer "12".
LS: (left side)
x + 9
= 12 + 9 Add
= 21
RS: (right side)
2x - 3
= 2(12) - 3 Multiply before subtracting
= 24 - 3 Subtract
= 21
Both sides equal to 21 when "x" is 12.
LS = RS left side equals right side
Therefore the answer is correct.
Answer:
D
Step-by-step explanation:
Given
- 12 ≤ 2x - 4 < 10 ( add 4 to all 3 intervals )
- 8 ≤ 2x < 14 ( divide all 3 intervals by 2 )
- 4 ≤ x < 7
Answer:
a) ![f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+264,034,000](https://tex.z-dn.net/?f=f%28t%29%3D0.001155%5B%5Cfrac%7B2%7D%7B3%7Dt%28t-1980%29%5E%7B3%2F2%7D-%5Cfrac%7B4%7D%7B15%7D%28t-1980%29%5E%7B5%2F2%7D%5D%2B264%2C034%2C000)
b) f(t=2015) = 264,034,317.7
Step-by-step explanation:
The rate of change in the number of hospital outpatient visits, in millions, is given by:
a) To find the function f(t) you integrate f(t):
![\int \frac{df(t)}{dt}dt=f(t)=\int [0.001155t(t-1980)^{0.5}]dt](https://tex.z-dn.net/?f=%5Cint%20%5Cfrac%7Bdf%28t%29%7D%7Bdt%7Ddt%3Df%28t%29%3D%5Cint%20%5B0.001155t%28t-1980%29%5E%7B0.5%7D%5Ddt)
To solve the integral you use:
Next, you replace in the integral:
Then, the function f(t) is:
![f(t)=0.001155[\frac{2}{3}t(t-1980)^{3/2}-\frac{4}{15}(t-1980)^{5/2}]+C'](https://tex.z-dn.net/?f=f%28t%29%3D0.001155%5B%5Cfrac%7B2%7D%7B3%7Dt%28t-1980%29%5E%7B3%2F2%7D-%5Cfrac%7B4%7D%7B15%7D%28t-1980%29%5E%7B5%2F2%7D%5D%2BC%27)
The value of C' is deduced by the information of the exercise. For t=0 there were 264,034,000 outpatient visits.
Hence C' = 264,034,000
The function is:
b) For t = 2015 you have:
![f(t=2015)=0.001155[\frac{2}{3}(2015)(2015-1980)^{1/2}-\frac{4}{15}(2015-1980)^{5/2}]+264,034,000\\\\f(t=2015)=264,034,317.7](https://tex.z-dn.net/?f=f%28t%3D2015%29%3D0.001155%5B%5Cfrac%7B2%7D%7B3%7D%282015%29%282015-1980%29%5E%7B1%2F2%7D-%5Cfrac%7B4%7D%7B15%7D%282015-1980%29%5E%7B5%2F2%7D%5D%2B264%2C034%2C000%5C%5C%5C%5Cf%28t%3D2015%29%3D264%2C034%2C317.7)
Its detailed and explained you also check your work and give where you get the info from.
