Question

A small dog weighs 6 1/2 pounds. A larger dog weighs 2 2/3 times as much as a small dog. How much does the larger dog weigh?​

Answer 1

Answer:The larger dog weighs 17 1/3 pounds .

Step-by-step explanation:6 1/2 ×  2 2/3

                                           = 13/2 ×   8/3

                                         = 104 /6  

                                         = 52/3

                                       = 17 1/3

That is how you solve it and the steps you do to get to the answer.

But now I will explain.So the first step is you change 6 1/2 and 2 2/3 into a improper fraction which 6 1/2 as an improper fraction is 13/2 and 2 2/3 as an improper fraction is 8/3 .The next  step is you multiply the improper fractions together which are 13/2 multiply 8/3 which you get 104/6.After that you simplify 104/6 ,and you get 52/3 . You divided both 104 and 6 (104/6) by 2 which gives you 52/3. (104 ÷ 2  /6 ÷ 2 =52/3) Lastly you change 52/3 which is a improper fraction into a mixed number which gives you 17 1/3 as your answer.

I hope this helps :)

Please give brainliest if it helps .Thanks :)

                             

Answer 2

Answer:

17 1/3 pounds

Step-by-step explanation:

6 1/2=6.5

6.5×2=13

6.5×2/3=4.3333333333

13+4.33=17.33=17 1/3

So the larger dog weighs 17 1/3 pounds

Please give brainliest, thank me and rate it 5 if this helped you.