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coldgirl [10]
3 years ago
5

Pls can you help me answer all of them

Mathematics
1 answer:
MaRussiya [10]3 years ago
3 0

Answer:

dk

Step-by-step explanation:

dk search it up u may find sum help

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❗️5 points❗️<br> 5. state the slope of the line. <br> A. -2 <br> B. 0 <br> C. 1 <br> D. Undefined
Anna35 [415]

Hey there! :)

Answer:

B. 0

Step-by-step explanation:

On the graph, the line is a horizontal line. This means that there is no change in the y-value across the domain.

Thus, the graph has a slope of 0.

4 0
3 years ago
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Katherine wants to prove that the measures of the interior angles of a triangle have a sum of 180. She draws a triangle and exte
Oliga [24]

Answer:

As we know, if we add up the interior and exterior angles of one corner of a triangle, we always get 180. the exterior angle in question is equal to the sum of the other two angles in the triangle

8 0
3 years ago
In the figure below, angle 1=(x+42)° and angle 2=2x° Find the angle measures.
Blababa [14]

Answer:

Step-by-step explanation:

4 0
1 year ago
The lengths of the sides of a triangle are 3, 4, 5. Can the triangle be a right triangle?
attashe74 [19]
Yes, this is a typical pythagorean triad.

Since the theorem is: c^{2} =  a^{2} +  b^{2}
And by inspection, 5^{2} would be the hypotenuse,
5^{2} =  3^{2} +  4^{2}
25 = 9 + 16
RHS = 9 + 16 = 25 = LHS
Therefore, we have proved that the values fit into pythagoras' theorem, which means that the triangle is a right triangle (that is the central idea of this theorem).
3 0
3 years ago
Find the point on the hyperbola xy= 8 that is closet to the point (3,0)
son4ous [18]
The distance l between (x, y) and (3, 0) is:
l=\sqrt{(0-y)^{2}+(3-x)^{2}}=\sqrt{y^{2}+(3-x)^{2}}

Since the equation of the hyperbola is xy=8, we can get y by itself and end up with
y=\frac{8}{x}

which we can plug into our distance formula:
l=\sqrt{(\frac{8}{x})^{2}+(3-x)^{2}}

To make calculation easier, we'll square both sides:
l^{2}=(\frac{8}{x})^2+(3-x)^{2}
and create a new variable m=l^{2}:
m=(\frac{8}{x})^2+(3-x)^{2}
\rightarrow m=\frac{64}{x^{2}}+9-6x+x^{2}

Differentiate both sides:
\frac{dm}{dx}=-\frac{128}{x^{3}}-6+2x
Minimum distance is achieved when \frac{dm}{dx}=0:
-\frac{128}{x^{3}}-6+2x=0
\rightarrow -128-6x^{3}+2x^{4}=0
\rightarrow 2(x^{4}-3x^{3}-64)=0
\rightarrow x^{4}-3x^{3}-64=0

To find a value of x, you can use methods like synthetic division and get the answer x=4

Plug into xy=8:
4y=8
\rightarrow y=2

So the closest point on the hyperbola to (3, 0) is (4, 2)
7 0
3 years ago
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