Question

The point Q has coordinates (2,3)

Answer 1

Answer:

b= (2a+11)/5

Step-by-step explanation:

5x + 2y = 9

2y=9-5x

y= 9/2 - 5x/2

slope, m1= -5/2

for perpendicularity, m1 × m2 = -1

slope for QR= m2=

$= - 1 \div \frac{ - 5}{2} = - 1 \times \frac{2}{ - 5} = \frac{ - 2}{ - 5} = \frac{2}{5}$

m2 is 2/5

$qr = \frac{b - 3}{a - 2}$

$\frac{2}{5} = \frac{b - 3}{a - 2}$

5(b-3)=2(a-2)

5b-15=2a-4

5b=2a-4+15

5b= 2a+11

$b = \frac{2a + 11}{5}$

Answer 2

Step-by-step explanation:

QR perp = y=-2.5x+4.5

QR gradient = 2/5

y=mx+c

3=(2/5)(2)+c

c=11/5

y=2/5x+11/5

b=2/5a+11/5

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