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sveticcg [70]
3 years ago
7

A ladybug crawls vertically on a leaf. Its motion is shown on the following graph of vertical position y vs. time t. What is the

ladybugs distance?

Physics
1 answer:
ella [17]3 years ago
7 0

Answer: 0 m/s

Explanation: The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.

We know that, the slope of a position-time graph gives velocity of an object. It can be given by :

In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.

It means its velocity is equal to at this time or we can say that ladybug is at rest.

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Kinetic Energy =  1/2 * mv²

Kinetic Energy = 14 J,  v = 2.3 m/s ,  m = ?

14  =      1/2 * m* 2.3²

14 = 0.5*m*2.3*2.3

m =  14 / (0.5*2.3*2.3)

m = 5.29 kg.

Mass = 5.29 kg.
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