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sveticcg [70]
3 years ago
7

A ladybug crawls vertically on a leaf. Its motion is shown on the following graph of vertical position y vs. time t. What is the

ladybugs distance?

Physics
1 answer:
ella [17]3 years ago
7 0

Answer: 0 m/s

Explanation: The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.

We know that, the slope of a position-time graph gives velocity of an object. It can be given by :

In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.

It means its velocity is equal to at this time or we can say that ladybug is at rest.

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labwork [276]

Answer:

Light provides brightness to see and also light carries energy

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3 years ago
The launching velocity of a missile is 20.0 m/s, and it is shot at 53º above the horizontal. What is the vertical component of t
Margaret [11]
The vertical component is given by the sin of the angle.  So this is 20*sin(53)=15.97m/s
8 0
3 years ago
What are some forces acting on you now that you can't see? PLS HELP!!!!!!
RideAnS [48]

also displayed the effects of sound being an invisible force of our world. Sound are frequencies. Different frequencies shape matter differently as you’ve seen.

Now, the human ear can only hear frequencies to a certain extent. When you take a hearing test at the doctors, they test your hearing by playing different tones (frequencies) in your ear. As people get older they will not be able to hear higher frequencies.

6 0
3 years ago
Read 2 more answers
Find the shear stress and the thickness of the boundary layer (a) at the center and (b) at the trailing edge of a smooth flat pl
melomori [17]

Answer:

a) The shear stress is 0.012

b) The shear stress is 0.0082

c) The total friction drag is 0.329 lbf

Explanation:

Given by the problem:

Length y plate = 2 ft

Width y plate = 10 ft

p = density = 1.938 slug/ft³

v = kinematic viscosity = 1.217x10⁻⁵ft²/s

Absolute viscosity = 2.359x10⁻⁵lbfs/ft²

a) The Reynold number is equal to:

Re=\frac{1*3}{1.217x10^{-5} } =246507, laminar

The boundary layer thickness is equal to:

\delta=\frac{4.91*1}{Re^{0.5} }  =\frac{4.91*1}{246507^{0.5} } =0.0098 ft

The shear stress is equal to:

\tau=0.332(\frac{2.359x10^{-5}*3 }{1}  )(246507)^{0.5} =0.012

b) If the railing edge is 2 ft, the Reynold number is:

Re=\frac{2*3}{1.215x10^{-5} } =493015.6,laminar

The boundary layer is equal to:

\delta=\frac{4.91*2}{493015.6^{0.5} } =0.000019ft

The sear stress is equal to:

\tau=0.332(\frac{2.359x10^{-5}*3 }{2}  )(493015.6^{0.5} )=0.0082

c) The drag coefficient is equal to:

C=\frac{1.328}{\sqrt{Re} } =\frac{1.328}{\sqrt{493015.6} } ==0.0019

The friction drag is equal to:

F=Cp\frac{v^{2} }{2} wL=0.0019*1.938*(\frac{3^{2} }{2} )(10*2)=0.329lbf

7 0
3 years ago
Friction always opposes ___________ motion​
Mariulka [41]
ANSWER: Friction is a force that opposes motion. When two objects are in contact, friction is acts in a direction opposite to the motion of the object.


EXPLANATION: HOPE THIS HELPS.
3 0
4 years ago
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