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sveticcg [70]
3 years ago
7

A ladybug crawls vertically on a leaf. Its motion is shown on the following graph of vertical position y vs. time t. What is the

ladybugs distance?

Physics
1 answer:
ella [17]3 years ago
7 0

Answer: 0 m/s

Explanation: The attached figure shows the position-time graph of a ladybug. We need to find the average speed of the ladybug between t = 4 s to t = 7 s.

We know that, the slope of a position-time graph gives velocity of an object. It can be given by :

In this case, the position of a ladybug at t = 4 s and at t = 7 s is the same i.e. 2 m.

It means its velocity is equal to at this time or we can say that ladybug is at rest.

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The wavelength of the first harmonic of the standing wave is 2L.

<h3>What is a standing wave?</h3>

A standing wave is one in which the obvious points remain fixed as the vibration continues. A standing wave occurs in a wind instrument such as a trumpet, saxophone etc.

We know from  the formula of the first harmonic that the wavelength of the first harmonic of the standing wave is 2L.

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3 0
2 years ago
Increasing the temperature of object by 20K = C *
Whitepunk [10]

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B

Explanation:

6 0
3 years ago
PLSS HELP AND I WILL GIVE BRAINLY TO THE ONE WHO ANSWERS CORRECTLY
Ierofanga [76]

The potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

<h3>What is resistance?</h3>

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The energy in terms of the charge and potential difference is;

E= qV

60=5 C × V

V= 12 V

The electric current is found as;

\rm I= \frac{q}{t} \\\\ I= \frac{5}{1.25}\\\\ I=4 \ A

From the ohm's law;

V=IR

12=4 ×R

R=3Ω

If the voltage is constant and the resistance is doubled, then the new electric current is half of the previous condition;

\rm I'=\frac{I}{2} \\\\ I'=\frac{4}{2} \\\\\ I'=2 \ A

Hence, the potential difference,electric current ,resistance and new electric current will be 12 V,4 A,3 Ω,2 A.

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7 0
2 years ago
A top-gun pilot, practising radar avoidance maneuvers, is manually flying horizontally at 1300km/h, just 35m above the level gro
IRINA_888 [86]
Tan x = AC / BC

tan (4.3) =  35 / BC

BC = 35 / tan (4.3)  = 465.485 m

Speed  = 1300 km/h = 361.111 m/s

465.485 / 361.111 m/s = 1.289 seconds

hope this helps
4 0
4 years ago
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