What is the difference between contact force and force at a distance

givi [52]

GREAT QUESTION! Cool subject to talk about :) Here goes nothing lol

1) Apache- North American Indians of the Southwest who fought against frontiersmen.
2) Arapaho- North American Plains Indians living along the Platte and Arkansas Rivers.
3) Sam Bass- A desperado whose career inspired ballads.
4) Judge Roy Bean- a legendary frontier judge who ruled by one book and a six-shooter!
5) Colt .45 six-shot revolver invented by Samuel Colt and used throughout the West... extremely popular among cowboys and outlaws alike.
6) Last but definetily not last, "Billy the Kid" (William H. Bonney, 1859-1881) Brooklyn-born gunman of the Wild West. Legendary Outlaw.
There are plenty more facts to talk about but in the interest of time this all I can provide for now. Hope it helps and have a nice day/night :)

4 0

3 years ago

Read 2 more answers

An object, located 80.0 cm from a concave lens, forms an image 39.6 cm from the lens on the same side as the object. What is the

kramer

Answer:

-78.4 cm

Explanation:

We can solve the problem by using the lens equation:

$\frac{1}{f}=\frac{1}{p}+\frac{1}{q}$

where

p is the distance of the object from the lens

q is the distance of the image from the lens

f is the focal length

Here we have

p = 80.0 cm

q = -39.6 cm (negative, because the image is on the same side as the object , so it is a virtual image)

Substituting, we find f:

$\frac{1}{f}=\frac{1}{80.0 cm}+\frac{1}{-39.6 cm}=-0.0128 cm^{-1}$

$f=\frac{1}{0.0128 cm^{-1}}=-78.4 cm$

5 0

4 years ago

If a Ferrari, with an initial velocity of 10m/s, accelerates at at rate of 50m/s/s for 3 seconds, what will its final velocity b

seraphim [82]

Answer:

160 m/s

Explanation:

The Ferrari is moving by uniformly accelerated motion, with constant acceleration of a = 50 m/s^2, and initial velocity u = 10 m/s. The velocity at time t of the car is given by

$v(t)= u +at$

where

u = 10 m/s

a = 50 m/s^2

If we substitute t = 3 s into the equation, we can find the velocity of the car after 3 seconds:

$v(3 s)=10 m/s + (50 m/s^2)(3 s)=160 m/s$

5 0

3 years ago

For Part A, Sebastian decided to use the copper cylinder. How would the magnitude of his q and ∆H compare if he were to redo Par

Vitek1552 [10]

The magnitudes of his q and ∆H for the copper trial would be lower than the aluminum trial.

The given parameters;

initial temperature of metals, = $T_m$
initial temperature of water, = $T_i$
specific heat capacity of copper, $C_p$ = 0.385 J/g.K
specific heat capacity of aluminum, $C_A$ = 0.9 J/g.K
both metals have equal mass = m

The quantity of heat transferred by each metal is calculated as follows;

Q = mcΔt

For copper metal, the quantity of heat transferred is calculated as;

$Q_p = (m_wc_w + m_pc_p)(T_m - T_i)\\\\Q_p = (T_m - T_i)(m_wc_w ) + (T_m - T_i)(m_pc_p)\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m_p(T_m - T_i)\\\\m_p = m\\\\Q_p = (T_m - T_i)(m_wc_w ) + 0.385m(T_m - T_i)\\\\let \ (T_m - T_i)(m_wc_w ) = Q_i, \ \ \ and \ let \ (T_m- T_i) = \Delta t\\\\Q_p = Q_i + 0.385m\Delta t$

The change in heat energy for copper metal;

$\Delta H = Q_p - Q_i\\\\\Delta H = (Q_i + 0.385m \Delta t) - Q_i\\\\\Delta H = 0.385 m \Delta t$

For aluminum metal, the quantity of heat transferred is calculated as;

$Q_A = (m_wc_w + m_Ac_A)(T_m - T_i)\\\\Q_A = (T_m -T_i)(m_wc_w) + (T_m -T_i) (m_Ac_A)\\\\let \ (T_m -T_i)(m_wc_w) = Q_i, \ and \ let (T_m - T_i) = \Delta t\\\\Q_A = Q_i \ + \ m_Ac_A\Delta t\\\\m_A = m\\\\Q_A = Q_i \ + \ 0.9m\Delta t$