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Aneli [31]
3 years ago
7

Friction always opposes ___________ motion​

Physics
1 answer:
Mariulka [41]3 years ago
3 0
ANSWER: Friction is a force that opposes motion. When two objects are in contact, friction is acts in a direction opposite to the motion of the object.


EXPLANATION: HOPE THIS HELPS.
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The efficiency of a squeaky pulley system is 73 percent. The pulleys are usedto raise a mass to a certain height. What force is
larisa86 [58]

The efficiency of the machine is defined as

\eta = \frac{W_{out}}{W_{in}}

Here

Work out is the work output and Work in is the work input

To find the Work in we have then

W_{in} = \frac{W_{out}}{\eta}

W_{in} = \frac{mgh}{\eta}

Replacing with our values

W_{in} = \frac{(58)(9.8)(3)}{73\%}

W_{in} = 2335.89J

The work done by the applied force is

W = Fd

Here,

F = Force

d = Distnace

Rearranging to find F,

F = \frac{W}{d}

F = \frac{2335.89J }{18}

F = 129.77N

Therefore the force exerted on the machine after rounding off to two significant figures is 130N

8 0
3 years ago
A bag is dropped from a balloon that is 50m above the ground and rising at 15m/s. calculate
ANTONII [103]

Answer:

See the answers below

Explanation:

We can solve this problem using the principle of energy conservation. That is, the energy is conserved before and after dropping the bag.

For this case we have mechanical energy, which is the sum of the kinetic and potential energies.

E_{1}=E_{2}

where:

E_{1}=E_{k}+E_{p}\\E_{2}=E_{p}

Ek = kinetic energy [J] (units of Joules)

Ep = potential energy [J]

In the final Energy (2), there is only potential energy. since when the balloon reaches the maximum height its velocity is zero, that is, there is no kinetic energy.

A)

m*g*h+\frac{1}{2}*m*v^{2} =m*g*h_{1} \\9.81*50+0.5*(15)^{2}=9.81*h_{1}\\h_{1} = 61.46 [m]

B)

With the value calculated above we can find the acceleration of the balloon.

The distance traveled is the difference between the maximum height and 50 meters.

x = 61.46-50\\x = 11.46[m]

With the following equation of kinematics.

v_{f}^{2} =v_{o}^{2}+2*a*x

0 = 15^{2} +2*a*11.46\\a = - 9.816 [m/s^{2} ]

The negative sign indicates that the acceleration acts downward. That is, in the opposite direction to the movement.

We can use the following equation of kinematics to find the final velocity after 4 seconds.

v_{f}=v_{o}-a*t\\v_{f}=15-9.816*(4)\\v_{f}=-24.24 [m/s]

Now the distance:

v_{f}^{2} =v_{o}^{2}-2*a*x\\(24.24)^{2} =(15)^{2} -2*9.81*x\\x = 18.48 [m]\\x_{f}=50+18.48 = 68.48 [m]

c) Using the following equation of kinematics.

v_{f}=v_{o}-a*t\\0 = 15-9.81*t\\15=9.81*t\\t = 1.52 [s]

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Calculate the impulse of a 1kg box that starts from rest and accelerates to 50m/s over a period of 10 seconds.
fomenos

Answer:

please find attached pdf

Explanation:

Download pdf
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3 years ago
A 14300 kg airplane is flying at an altitude of 147 m at a speed of 214 m/s. determine the airplane's total mechanical energy.
kakasveta [241]

Answer:

Mechanical energy in Joules:

348,041,980

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