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Aleks04 [339]
3 years ago
6

Atoms are composed of protons, ______, and electrons.​

Physics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Atoms are composed of protons, \sf\purple{neutrons}and electrons. ✅

  • The \sf\blue{protons} (positively charged) and the \sf\pink{neutrons} (no charge) are in the centre of the atom, making up the nucleus.
  • \sf\red{Electrons} (negatively charged) are present in the outermost shell of the atom.

\bold{ \green{ \star{ \orange{Hope\:it\:helps.}}}}⋆

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A passenger at an airport pulls a rolling suitcase by its handle. If the force used is 10 N and the handle makes an angle of 25
Deffense [45]

Answer:

W= 1812.6 J

Explanation:

Work (W) is defined as the scalar product of force F by the distance (d) the body travels due to this force.  

W= F*d* cosα Formula ( 1)

Where:

F is the force in Newtons (N)

d is the displacemente in meters (m)

α : Angle formed between force and displacement

Data

F = 10 N

d = 200 m

α = 25°

Work done by the pulling force while the passenger walks 200 m

We replace data in the formula (1)

W= F*d* cosα

W= (10 N)*(200 m)* cos25°

W= 1812.6 (N*m)

W= 1812.6 J

6 0
3 years ago
A heavy rope, 60 ft long, weighs 0.5 lb/ft and hangs over the edge of a building 130 ft high. (Let x be the distance in feet bel
Nataliya [291]

Answer:

Riemann sum

W = lim n→∞ Σ 0.5xᵢΔx (with the summation done from i = 1 to n)

Integral = W = ∫⁶⁰₀ 0.5x dx

Workdone in pulling the entire rope to the top of the building = 900 lb.ft

Riemann sum for pulling half the length of the rope to the top of the building

W = lim n→∞ Σ 0.5xᵢΔx (but the sum is from i = 1 to n/2)

Integral = W = ∫⁶⁰₃₀ 0.5x dx

Work done in pulling half the rope to the top of the building = 675 lb.ft

Step-by-step explanation:

Using Riemann sum which is an estimation of area under a curve

The portion of the rope below the top of the building from x to (x+Δx) ft is Δx.

The weight of rope in that part would be 0.5Δx.

Then workdone in lifting this portion through a length xᵢ ft would be 0.5xᵢΔx

So, the Riemann sum for this total work done would be

W = lim n→∞ Σ 0.5xᵢΔx (with the summation done from i = 1 to n)

The Riemann sum can easily be translated to integral form.

In integral form, with the rope being 60 ft long, we have

W = ∫⁶⁰₀ 0.5x dx

W = [0.25x²]⁶⁰₀ = 0.25 (60²) = 900 lb.ft

b) When half the rope is pulled to the top of the building, 60 ft is pulled up until the length remaining is 30 ft

Just like in (a)

But the Riemann sum will now be from the start of the curve, to it's middle

Still W = lim n→∞ Σ 0.5xᵢΔx (but the sum is from i = 1 to n/2)

W = ∫⁶⁰₃₀ 0.5x dx

W = [0.25x²]⁶⁰₃₀ = 0.25 (60² - 30²) = 675 lb.ft

Hope this Helps!!!

7 0
3 years ago
A rigid rectangular loop, which measures 0.30 m by 0.40 m, carries a current of 5.5 A, as shown in the figure. A uniform externa
slamgirl [31]

Answer:

The magnitude will be "(1.097 \ N/m)\hat{j}". The further explanation is given below.

Explanation:

Trying to determine what is usual for a rectangular loop plane,

⇒  \hat{n}=(Cos35^{\circ})(-\hat{i})+(Sin35^{\circ})(\hat{k})

Magnetic moment is given as:

μ = IA\hat{n}

On putting the values in the above formula, we get

μ = (5.5A)[(0.3m)(0.4m)][(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(-\hat{k})]

  = 0.66 Am^2[(Cos35^{\circ})(\hat{i})+(Sin35^{\circ})(\hat{k})]

Now the external vector-shaped torque seems to be:

Magnitude,

\sigma=\hat{\mu}\times\hat{\beta}

On putting the values in the above formula, we get

⇒ \sigma=[(0.06Am^2)(Cos35^{\circ}(-\hat{i})+Sin35^{\circ}(-\hat{k})]\times (2.9T)(-\hat{i})

⇒    = (0.66)(2.9)Cos35^{\circ}(\hat{i}\times \hat{i})+(0.66)(2.9)Sin35^{\circ}(\hat{k}\times \hat{k})

⇒    = 0+(1.97 \ N/m)\hat{j}

⇒    =(1.097 \ N/m)\hat{j}

8 0
3 years ago
Cheryl has a mug that she says is made up of matter. Heather says that the hot chocolate inside the cup is made up of matter, to
natulia [17]
Everyone except Mikayla is correct.
4 0
3 years ago
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You are pushing a 7.5kg block. It is moving at 2.3m/s when you release your push. It takes 2 seconds to stop. Find the coefficie
IRISSAK [1]
Hope this helps you.

5 0
4 years ago
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