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Alex777 [14]
3 years ago
14

*PLEASE HELP*

Physics
2 answers:
kotegsom [21]3 years ago
5 0

Answer: The focal length of the lens = 3.32 cm.

Explanation:

Lens formula : \dfrac1f=\dfrac1v-\dfrac1u    (i)

f= focal length , v=image distance , u =object distance.

magnification: m = \dfrac{v}{u}   (ii )

Given: v= -12.8 cm , m =2.85

Put values in (ii), we get

2.85=\dfrac{-12.8}{u}\\\\\Rightarrow\ u=\dfrac{-12.8}{2.85}\\\\\Rightarrow\ u=-4.49\  cm

substitute values of u , v in (i)

\dfrac1f=\dfrac1{-12.8}-\dfrac{1}{4.49}\\\\\Rightarrow\dfrac1f=-0.30084214922\\\\\Rightarrow\ f=\dfrac{-1}{-0.30084214922}\approx3.32\ cm

Hence, the focal length of the lens = 3.32 cm.

GuDViN [60]3 years ago
4 0

Answer:

6.92

Explanation:

2.85=-(-12.8/x)

do=4.49

1/f= 1/4.49 + 1/-12.8

f=6.92

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