All categories

3 years ago

If the forces acting upon an object are balanced, then an object MUST

Physics

1 answer:

yulyashka [42]3 years ago

7 0

Stationary at rest or moving with constant motion

Explanation:

If the force acting upon an object are balanced, the object must be stationary or at rest or moving with constant velocity.

According to newton's first law of motion;

"An object will remain in its state of rest or of uniform motion unless acted upon by an external force".

This suggests that body at rest has balanced forces acting upon it.

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

You might be interested in

Wireless Internet networks, including many used in homes, often make use of high-frequency radio waves. High-frequency waves are

lutik1710 [3]

The answer is d , small disruptions

4 0

3 years ago

Read 2 more answers

Of the eight most abundant elements in earths crust, what percentage does the six next most abundant elements of earths crust ma

Mrac [35]

Answer:

the sixth most abundant element in the earth's crust is sodium and it occupies 2.8%

5 0

4 years ago

Two velcro-covered pucks slide across the ice, collide and stick to one another. Their interaction with the ice is frictionless.

balu736 [363]

Answer:

1. False

2. True

3. False

4. True

Explanation:

Conservation of Momentum

According to the law of conservation of linear momentum, the total momentum of the system formed by both pucks won't change regardless of their interaction if no external forces are acting on the system.

The momentum of an object of mass ma moving at speed va is

$p_a=m_a.v_a$

The total momentum of both pucks at the initial condition is

$p_1=m_a.v_a+m_b.v_b$

Both pucks are moving to the right and puck B has twice the mass of puck A (let's call it m), thus

$m_a=m$

$m_b=2m$

We are given

$v_a=6\ m/s\\v_b=2\ m/s$

The total initial momentum is

$p_1=6m+2(2m)=10m$

At the final condition, both pucks stick together, thus the total mass is 3m and the final speed is common, thus

$p_2=3m.v'$

Equating the initial and final momentum

$10m=3m.v'$

Solving for v'

$v'=10/3\ m/s=3.33\ m/s$

1. Compute the initial kinetic energy:

$\displaystyle K_1=\frac{1}{2}mv_a^2+\frac{1}{2}2mv_b^2$

$\displaystyle K_1=\frac{1}{2}m\cdot 6^2+\frac{1}{2}2m\cdot 2^2$

$K_1=18m+4m=22m$

The final kinetic energy is

$\displaystyle K_2=\frac{1}{2}mv'^2+\frac{1}{2}2mv'^2$

$\displaystyle K_2=\frac{1}{2}m\cdot 3.33^2+\frac{1}{2}2m\cdot 3.33^2$

$K_2=16.63m$

As seen, part of the kinetic energy is lost in the collision, thus the statement is False

2. The initial speed of puck B was 2 m/s and the final speed was 3.33 m/s, thus it increased the speed: True

3. The initial speed of puck A was 6 m/s and the final speed was 3.33 m/s, thus it decreased the speed: False

4. The momentum is conserved since that was the initial assumption to make all the calculations. True

$p_1=10m$

$p_2=3m.v'=3m(10/3)=10m$

Proven

5 0

3 years ago

3. Question

aalyn [17]

2. Newton's laws of motion

5 0

3 years ago

Read 2 more answers

PLEASE help me quickly

Anna007 [38]

Explanation:

its either a or d however i say the best choice is d

6 0

3 years ago