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alexandr402 [8]
3 years ago
9

shasha worked in the garden for 3 hours and 40 minutes. she started at 8:30am. at what time did she stop?

Mathematics
2 answers:
eimsori [14]3 years ago
3 0

Answer:

Sasha stopped working at 12:10 PM

Step-by-step Explanation

8:30 + 3 hours and 40 minutes = 12:10 PM

Mark as brainliest if it's right!

vovangra [49]3 years ago
3 0

Answer:

12:10 p.m

Step-by-step explanation:

3 hours from 8:30 is 11:30 a.m.

Now we add 30 minutes to 11:30 and you get 12:00

Add the remaining 10 minutes and you get 12:10 p.m

I hope this helped, please mark Brainliest, thank you!

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Solve -7/2=-28 please solve and show work
Assoli18 [71]

Step-by-step explanation:

-7/2 = -28

-7 = -28 × 2

-7 = -56

5 0
3 years ago
In the figure to the right, can you conclude that triangle GHI is congruent to triangle KJI? Justify your reasoning.
inessss [21]

Answer:

No

Step-by-step explanation:

You cannot conclude that ΔGHI is congruent to ΔKJI, because although you can see/interpret that there all the angles are congruent with one another, like with vertical angles (∠GIH and ∠KIJ) and alternate interior angles (∠H and ∠J, ∠G and ∠K), we don't know the side lengths.

All the angles could be congruent, but the sides might be different. For example, ΔGHI might be a bigger triangle than ΔKJI, which could make them similar to one another, but not congruent.

For something to be congruent to another, everything must be exactly the same.

7 0
3 years ago
Nvm bro i got the answer
KIM [24]
Ok and have a nice day
6 0
3 years ago
How do you write 39/50 as a percentage?
Allushta [10]
We can convert the fraction to a denominator of 100, since percents are parts of 100.

39 * 2 = 78
50 * 2 = 100

So we have 78/100 or 78%
4 0
3 years ago
Read 2 more answers
If f(x)=x2-2x-8 and g(x)=1/4x-1 for which value of x is f(x)=g(x)
fomenos

f(x)=x^2-2x-8;\ g(x)=\dfrac{1}{4}x-1\\\\f(x)=g(x)\iff x^2-2x-8=\dfrac{1}{4}x-1\qquad\text{multiply both sides by 4}\\\\4x^2-8x-32=x-4\qquad\text{subtract x from both sides}\\\\4x^2-9x-32=-4\qquad\text{add 4 to both sides}\\\\4x^2-9x-28=0\\\\4x^2-16x+7x-28=0\\\\4x(x-4)+7(x-4)=0\\\\(x-4)(4x+7)=0\iff x-4=0\ \vee\ 4x+7=0\\\\x=4\ \vee\ 4x=-7\\\\\boxed{x=4\ \vee\ x=-\dfrac{7}{4}}

6 0
3 years ago
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