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marissa [1.9K]
2 years ago
13

Mr Macdonald recorded the test mark for his eight grade class of 25 students he used the marks recorded to calculate the average

to be 72 Sandra's marks of 86 was incorrectly marked as 36 what is the correct average for this test
Mathematics
1 answer:
Andrew [12]2 years ago
6 0
Literal or figurative language is the answer !
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Determine whether n^2+20n+100 is a perfect square trinomial.<br><br> Yes<br><br> No
Black_prince [1.1K]
N²+20n+100 = (n+10)(n+10)
Yes is it a perfect square trinomial
7 0
3 years ago
Richard walks every day for exercise at a rate of 1 kilometer every 20 minutes.
OleMash [197]

Answer:

3000 meters

Step-by-step explanation:

1 kilometer = 1000 meters

1 kilometers = every 20 minutes

3× 1000 meters= 20 min ×3

3000 meters = 60 min/ 1 hour

7 0
2 years ago
Diego has $500 in his savings account. Each month, he takes out $20 to pay for karate class.
Firlakuza [10]

Answer:

500- (m*20)=?

Step-by-step explanation:

3 0
2 years ago
The expression 2.5a+2b gives the cost (in dollars) for a DVDs and b CDs at a moving sale. a. The cost for 1 DVD is $ and the cos
Mekhanik [1.2K]

Answer/Step-by-step Explanation:

Given:

a = no. of DVDs

b = no. of CDs

Total cost ($) for DVDs and CDs = 2.5a + 2b

a. The cost for 1 DVD = 2.5(a) = 2.5(1) = $2.5

The cost for 1 CD = 2(b) = 2(1) = $2

b. Total cost for 4 DVDs and 4 CDs:

Substitute a = 4, and b = 4 into the equation.

2.5(4) + 2(4)

10 + 8 = 18

Total cost for 4 DVDs and 4 CDs = $18

c. To find out if $20 would be enough to buy 6 DVDs and 3 CDs, substitute a = 6, and b = 3 into the equation. Solve for the total cost to see if it equals $20 or is less than $20. If it's greater than $20, then it won't be enough.

2.5(6) + 2(3)

15 + 6 = 21

6 DVDs and 3 CDs cost more than $20, therefore, $20 is not enough.

5 0
2 years ago
Stefan purchases materials to make dog collars. Stefan purchases 10 buckles in a pack and 12 straps in a pack. Stefan doesn't wa
CaHeK987 [17]

Answer:

No

Step-by-step explanation:

Assuming it take 1 buckle and 1 strap per collar, that means we just need to find the lowest common multiple of these 10-pack buckles and 12-pack straps.

For 10: 0, 10, 20, 30, 40, 50, "60", 70, 80, 90, 100...

For 12: 0, 12, 24, 36, 48, "60", 72, 84, 96, 108, 120...

From this, it is obvious that 60 is the lowest common multiple of these two numbers. Therefore, we know that Stefan can make dog collars without having leftover supplies by using 6 10-pack buckles and 5 12-pack straps.

From this, we know that Stefan does not need to buy 120 of either the buckles or the straps.

5 0
3 years ago
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