Answer:

Step-by-step explanation:
Given
Normal Hour = 32 hours
Overtime = Hours above 32
Rate for Overtime = 1.4 times normal rate
Earnings = $535.62
Required
Determine the normal hour pay
First, we need to determine the hours worked overtime.
This is:


The equation that binds all the parameters is:

This gives:



Solve for r


F(6) says “take f(x) = -4x + 11 and put 6 in for every x-value and then clean it up.”
f(6) = -4(6) + 11
= -24 + 11
= -13
f(x) = -1 says “set your function equal to -1 and solve for x”
f(x) = -1
-4x+11 = -1
-4x = -12
x = 3
So f(3) = -1.
By apply the distributive property of multiplication, the value of k which makes the statement true is 1.
<h3>What is the
distribution property?</h3>
Mathematically, the distributive property of multiplication is given by tis expression:
x(y + z) = xy + xz.
Next, we would apply the distributive property of multiplication to the given equation by distributing to the left-hand side using xy⁴:
k(2x⁴y⁴ + 7x³y⁸) = 2x⁴y⁴ + 7x³y⁸
Dividing both sides by the common factor, we have:
k = (2x⁴y⁴ + 7x³y⁸)/(2x⁴y⁴ + 7x³y⁸)
k = 1.
In conclusion, the value of k which makes the statement true is 1.
Read more on distributive property here; brainly.com/question/2807928
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<u>Complete Question:</u>
What value of k makes the statement true?
y⁴(2x³ + 7x²y⁴) = 2x⁴y⁴ + 7x³y⁸
Given:
The system of equations is


To find:
The graph of the given system of equations and its solution.
Solution:
The table of values for
is
x y
-4 7
-2 2
0 -3
Plot these points and connect them by a straight line.
The table of values for
is
x y
-4 0
-2 2
0 4
Plot these points and connect them by a straight line.
From the below graph it is clear that the lines intersect each other at point (-2,2).
Therefore, the solution of given system of equation is (-2,2).
Answer:
a: 0.9544 9 within 8 units)
b: 0.9940
Step-by-step explanation:
We have µ = 300 and σ = 40. The sample size, n = 100.
For the sample to be within 8 units of the population mean, we would have sample values of 292 and 308, so we want to find:
P(292 < x < 308).
We need to find the z-scores that correspond to these values using the given data. See attached photo 1 for the calculation of these scores.
We have P(292 < x < 308) = 0.9544
Next we want the probability of the sample mean to be within 11 units of the population mean, so we want the values from 289 to 311. We want to find
P(289 < x < 311)
We need to find the z-scores that correspond to these values. See photo 2 for the calculation of these scores.
We have P(289 < x < 311) = 0.9940