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MAXImum [283]
3 years ago
5

Use the rule to write the first five terms of the pattern: Rule: add 8, subtract 4 First term: 13​

Mathematics
2 answers:
marysya [2.9K]3 years ago
6 0

Answer:

17

Step-by-step explanation:

13 + 8 - 4

pav-90 [236]3 years ago
6 0

Answer:

{13, 17, 21, 25, 29}

Step-by-step explanation:

Add 8 and subtract 4 is equivalent to Add 4.

If the first term is 13, the next is 17;

the second term is 21; and

the third term is 25.

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2^5×8^4/16=2^5×(2^a)4/2^4=2^5×2^b/2^4=2^c<br>A=<br>B=<br>C= <br>Please I'm gonna fail math
aleksley [76]

9514 1404 393

Answer:

  a = 3, b = 12, c = 13

Step-by-step explanation:

The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  (a^b)/(a^c) = a^(b-c)

  (a^b)^c = a^(bc)

___

You seem to have ...

  \dfrac{2^5\times8^4}{16}=\dfrac{2^5\times(2^3)^4}{2^4}\qquad (a=3)\\\\=\dfrac{2^5\times2^{3\cdot4}}{2^4}=\dfrac{2^5\times2^{12}}{2^4}\qquad (b=12)\\\\=2^{5+12-4}=2^{13}\qquad(c=13)

_____

<em>Additional comment</em>

I find it easy to remember the rules of exponents by remembering that <em>an exponent signifies repeated multiplication</em>. It tells you how many times the base is a factor in the product.

  2\cdot2\cdot2 = 2^3\qquad\text{2 is a factor 3 times}

Multiplication increases the number of times the base is a factor.

  (2\cdot2\cdot2)\times(2\cdot2)=(2\cdot2\cdot2\cdot2\cdot2)\\\\2^3\times2^2=2^{3+2}=2^5

Similarly, division cancels factors from numerator and denominator, so decreases the number of times the base is a factor.

  \dfrac{(2\cdot2\cdot2)}{(2\cdot2)}=2\\\\\dfrac{2^3}{2^2}=2^{3-2}=2^1

5 0
2 years ago
I will give BRAINIEST to the next person who answers this!!
sertanlavr [38]

Answer:

<u>Challenge #1:</u>

<u>Different examples:</u>

2x+1=3x+2

4x+3=5x+4

3x+2=4x+3

<u>Challenge #2:</u>

<u>Different examples:</u>

2x+0=4x+1

3x+1=2x+5

6x+5=8x+6

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juin [17]

Answer: point E

Step-by-step explanation:

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2 years ago
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zzz [600]
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Solve the following equation 3+3x+9(9x)
sertanlavr [38]

I believe that the answer is 3+84x is this question wants you to simplify the expression.

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