Let the numbers be x and y.
x*y=HCF*LCM=6*60=360
thus
y=360/x
next we find the list of combinations of x and y and test if they satisfy the conditions above:
(6,60),(12,30),(18,20),(24,15)
out of the above, only (6,60) and (12,30) satisfy both conditions. Thus our answer is:
(6,60) or (12,30)
Answer:
B. 0
Step-by-step explanation:
If you subtract the right side expression and simplify, you get ...
4/5(20x +5) -(16x -2) = 0
16x +4 -16x +2 = 0
6 = 0 . . . . . . . . . . . . false
There is no value of x that will make this true. There are no solutions.
The system of inequalities for the specific graph is
1. (one on top) y ≤ 1/2x + 6
2. (one on bottom) y > 1/2x -2
Hope this helped! :D
