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avanturin [10]
3 years ago
10

Can someone write out the steps on how to verify this identity?

Mathematics
1 answer:
zhenek [66]3 years ago
3 0

Step-by-step explanation:

(csc θ − 1) / cot θ

Multiply top and bottom by the conjugate csc θ + 1.

(csc θ − 1) (csc θ + 1) / (cot θ (csc θ + 1))

Distribute.

(csc²θ − 1) / (cot θ (csc θ + 1))

Use Pythagorean identity.

cot²θ / (cot θ (csc θ + 1))

Divide.

cot θ /  (csc θ + 1)

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Paper clips are sold in boxes of 1000.
belka [17]

Answer:

6.5%

Step-by-step explanation:

1000 in a box and he orders 5 boxes.

1000x5= 5000

So he orders 5000 paper clips

1 box is £15.40 and he order 5, so £15.40x5= £77

£77 is between £55 and £79.99 so he will get 6.5% discount.

After the discount he will pay  £71.99

8 0
3 years ago
If a spring stretches 6 meters when a 7-kilogram weight is attached to it, how much will it stretch when a 42-kilogram weight is
Zinaida [17]

Answer:

Step-by-step explanation:

 This is a simple proportion problems.

7 kilogram weight attache to a spring stretches  = 6 meters

 1 kilogram would stretch                                       =  6/7 m

Therefore 42 kilograms would  stretch                  = (6/7 x 42)meters

                                                                                 =  36 meters.

                                                                         

 

8 0
3 years ago
Which numbers in Set A = {−7, −4, 2, 14, 21, 34, 42} are elements of both Set B and Set C, shown below? Set B = {even numbers} S
sweet [91]

Answer:

14, 42

Step-by-step explanation:

Set A = {−7, −4, 2, 14, 21, 34, 42}

Set B = {even numbers}

Set C = {multiples of 7}

There is only one question asked

Which numbers in Set A are elements of both Set B and Set C,

We need it to be even and a multiple of 7

14 is even and a multiple of 7  and 42 is even and a multiple of 7

5 0
3 years ago
Read 2 more answers
The distribution of SAT scores of all college-bound seniors taking the SAT in 2014 was approximately normal with a mean of 14971
RideAnS [48]

Answer:

P(X<1200) is 0.8212

Step-by-step explanation:

Test statistic (z) = (X - mean)/sd

X is score of a tester = 1200

mean = 1497

sd = 322

z = (1200 - 1497)/322 = -297/322 = -0.92

The cumulative area of the test statistic is the probability that X<1200. The cumulative area is 0.8212.

Therefore, P(X<1200) = 0.8212

8 0
3 years ago
Read 2 more answers
Which conversion factors are used to multiply to 18cm/ s to get meters per minute?
Nimfa-mama [501]

Remark

The short answer is you multiply 0.6 times the cm/s to get m/min.

Solve

Though you didn't ask for it, here's the way it is done. Notice that each set of brackets cancels the units of a set of brackets to the left of the set of brackets you are observing. This is called unit analysis. The answer is given below.

\frac{18 cm}{sec} *[\frac{60 cm}{1 min}] * [\frac{1 m}{100 cm}] = 18*0.6\frac{m}{min}=10.8\frac{m}{min}

8 0
3 years ago
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