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Mashcka [7]
3 years ago
9

.

Mathematics
2 answers:
mrs_skeptik [129]3 years ago
8 0

Answer:

x ≈ 43.3°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos x = \frac{adjacent}{hypotenuse} = \frac{8}{11} , then

x = cos^{-1} (\frac{8}{11} ) ≈ 43.3° ( to 1 dec. place )

Anastasy [175]3 years ago
8 0
B° = x so refer that syllable to x

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PLEASE HELP! THANK YOUUUUU!
USPshnik [31]

I think its D)

Because when you look at the x-axis 3 and go up to the y-axis its 4

4 0
3 years ago
Read 2 more answers
Find equation of linear function represented by the table below in slope intercept form
icang [17]

Answer:

y=4x+3

Step-by-step explanation:

The slope of the line is (13-7)/(2-1)=4. The line equation is hence y=4x+3

7 0
3 years ago
3. Ethan bought a used car. The value, v(t) the car t years after his purchase is given by the equation v(t) = 4, 500 * (0.8334)
Nimfa-mama [501]

Answer: 4500

Step-by-step explanation: when t=0, then 0.8334^t= 1

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7 0
3 years ago
Design specifications require that a key dimension on a product measure 105 ± 12 units. A process being considered for producing
marta [7]

Answer:

Cpk = Cpu = Cpl = 0.4785

Step-by-step explanation:

Solution:-

- The capability of a process is determined using the capability index ( Cpk ). The index helps in determining the output of the process lies within the specification limits.

- The key dimension on a product measure is:

                                 105 ± 12 units

- Process is producing this product at a 6-sigma quality standards i.e ( process is producing this product has a standard deviation (σ) of three units.)

Where,         Standard Error in measured value = 12 units.

- The process capability (Cpu) is defined based on the Upper Specification Limit of the process (USL):

                             Cpu = (USL - u) / 3σ

- The process capability (Cpl) is defined based on the Lower Specification Limit of the process (LSL):

                             Cpl = ( u - LSL) / 3σ

- Assume that the process is centered with respect to specifications, then the given absolute value of u = 105 units.

Where the specification limits are defined as:

                             LSL = u - SE = 105 - 12

                             LSL = 93 units

                             USL = u + SE = 105 + 12

                             USL = 117 units

- Now evaluate the Process capability on each of the two limits specification limits:

                           Cpu = (USL - u) / 3σ

                           Cpu = (117 - 105) / 3σ

                           Cpu = 4 / σ

                           Cpl = ( u - LSL) / 3σ

                           Cpl = ( 105 - 99 ) / 3σ

                          Cpl = 4 / σ    

- The minimum of Cpu and Cpl is denoted as the Cpk value:

                           Cpk = min ( Cpu , Cpl )

                           Cpk = Cpu = Cpl = 4 / 8.36

                           Cpk = Cpu = Cpl = 4 / 8.36 = 0.4785          

               

6 0
3 years ago
If (x+2) is a factor of x^3-6x^2+kx+10, k=
Alja [10]
If a binomial (x-a) is a factor of a polynomial, then a is a root of this polynomial.

(x+2)=(x-(-2)) \Rightarrow a=-2\\\\
(-2)^3-6\cdot(-2)^2+k\cdot(-2)+10=0\\
-8-24-2k+10=0\\
-2k=22\\\
\boxed{k=-11}


3 0
3 years ago
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